Let a, b, and c be the times each pump will fill the tank when working alone.
Therefore, in 1 hour;
1/a +1/b = 1/(6/5) = 5/6 ---- (1)
1/a+1/c = 1/(3/2) = 2/3 ---- (2)
1/b+1/c = 1/(2) = 1/2 ---- (3)
From equation (1)
1/a = 5/6-1/b
Substituting for 1/a in eqn (2)
5/6-1/b+1/c = 2/3
-1/b +1/c = -1/6 => 1/c = 1/b - 1/6 --- (4)
Using eqn (4) in eqn (3)
1/b+1/b-1/6 = 1/2
2/b-1/6 = 1/2
2/b =1/2+1/6 = 2/3
1/b = 1/3
Then,
1/c = 1/3 - 1/6 = 1/6
1/a = 5/6 - 1/3 = 1/2
This means, in 1 hour and with all the pumps working together, the tank will be filled to;
1/a+1/b+1/c = 1/2+1/3+1/6 = 1 (filled fully).
Therefore, it will take 1 hour to fill the tank when all pumps are working together.
To isolate y, subtract 2.
y < 4x - 5The graph will be a dashed line y = 4x - 5 with the area below the line shaded.
Answer:


Step-by-step explanation:
Given
See attachment for graph
Solving (a): Increasing interval
To do this, we simply identify the interval at which the value of the graph increases.
The value has an increased interval between -2 and 1.5 (of the x-axis).
Hence, the increasing interval is:

Solving (b): Decreasing interval
To do this, we simply identify the interval at which the value of the graph decreases.
The value has decreased intervals between - infinity and -2 and also 1.5 and infinity (of the x-axis).
Hence, the decreasing interval is:

Answer:
The answer is 1470 seconds.
Step-by-step explanation: