Please please help me on this one!

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

3 0

Answer:

3422 x232

Step-by-step explanation:

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Notice the picture
we have, the opposite side
the angle
and we want the hypotenuse

so recall your SOH CAH TOA $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent} =$

which one has all that? low and behold, is Ms Sine,
so let's bother Ms Sine

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(27^o)=\cfrac{18}{hypotenuse}
\\\\\\
hypotenuse=\cfrac{18}{sin(27^o)}$

make sure your calculator is in Degree mode, since the angle here is in degrees, as opposed to Radian mode

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Answer:

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Step-by-step explanation:

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