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3 years ago

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Mathematics

2 answers:

Ilya [14]3 years ago

8 0

Answer:

I just took the test, this answer is 1.067

topjm [15]3 years ago

5 0

Let
x--------> the unknown scale size
we know that
N 1---------> x
N 2---------> 1
N 3---------> 0.937
N 4--------->0.878
scale factor=0.937/0.878------> 1.0672
to obtain the size N 3 ----> multiply the size N 4 by 1.0672
size N 3=1.0672*0.878-----> 0.937
so
to obtain the size N 2 ----> multiply the size N 3 by 1.0672
size N 2=1.0672*0.937------> 1

to obtain the size N 1 ----> multiply the size N 2 by 1.0672
size N =1.0672*1------> 1.0672
hence
x=1.0672-------> x=1.067

the answer is the unknown scale size is 1.067

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Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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3 years ago

Factorise mx+cx+my+cy With steps!!! x=algebra x

avanturin [10]

Step-by-step explanation:

Hey there!

While factorising you remember to make it take common in most of the expression.

Here;

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Take common 'x' in "mx+cx" and 'y' in my + cy.

= x(m+c) + y(m+c)

Now, "(m+c)" common again.

= (m+c) (x+y)

Therefore the factorized form of the expression in (m+c)(x+y).

Hope it helps...

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julsineya [31]

We are given

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$S=4\pi r^2$

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we can solve for r

$r=3.9989cm$

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$V=\frac{4}{3} \pi r^3$

we can plug r

$V=\frac{4}{3} \pi (3.9989)^3$

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Y_Kistochka [10]

Answer:

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