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kap26 [50]
3 years ago
5

Four sizes of scaled text are shown.

Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

I just took the test, this answer is 1.067

topjm [15]3 years ago
5 0
Let
x--------> the unknown scale size
we know that
N 1---------> x
N 2---------> 1
N 3---------> 0.937
N 4--------->0.878
scale factor=0.937/0.878------> 1.0672
to obtain the size N 3 ----> multiply the size N 4 by 1.0672
size N 3=1.0672*0.878-----> 0.937
so
to obtain  the size N 2 ----> multiply the size N 3 by 1.0672
size N 2=1.0672*0.937------> 1

to obtain  the size N 1 ----> multiply the size N 2 by 1.0672
size N =1.0672*1------> 1.0672
hence
x=1.0672-------> x=1.067

the answer is the unknown scale size is 1.067
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Gekata [30.6K]

Consider the digit expansion of one of the numbers, say,

676₉ = 600₉ + 70₉ + 6₉

then distribute 874₉ over this sum.

874₉ • 6₉ = (8•6)(7•6)(4•6)₉ = (48)(42)(24)₉

• 48 = 45 + 3 = 5•9¹ + 3•9⁰ = 53₉

• 42 = 36 + 6 = 4•9¹ + 6•9⁰ = 46₉

• 24 = 18 + 6 = 2•9¹ + 6•9⁰ = 26₉

874₉ • 6₉ = 5(3 + 4)(6 + 2)6₉ = 5786₉

874₉ • 70₉ = (8•7)(7•7)(4•7)0₉ = (56)(49)(28)0₉

• 56 = 54 + 2 = 6•9¹ + 2•9⁰ = 62₉

• 49 = 45 + 4 = 5•9¹ + 4•9⁰ = 54₉

• 28 = 27 + 1 = 3•9¹ + 1•9⁰ = 31₉

874₉ • 70₉ = 6(2 + 5)(4 + 3)10₉ = 67710₉

874₉ • 600₉ = (874•6)00₉ = 578600₉

Then

874₉ • 676₉ = 578600₉ + 67710₉ + 5786₉

= 5(7 + 6)(8 + 7 + 5)(6 + 7 + 7)(0 + 1 + 8)(0 + 0 + 6)₉

= 5(13)(20)(20)(1•9)6₉

= 5(13)(20)(20 + 1)06₉

= 5(13)(20)(2•9 + 3)06₉

= 5(13)(20 + 2)306₉

= 5(13)(2•9 + 4)306₉

= 5(13 + 2)4306₉

= 5(1•9 + 6)4306₉

= (5 + 1)64306₉

= 664306₉

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Answer:

The average age of pilots has a lower coefficient of variation, so it is the most consistent data set.

Step-by-step explanation:

The coefficient of variation is used to measure consistency of a data set. It is the standard deviation divided by the mean. The higher the coefficient of variation, the more variable, that is, the least consistent the data set is.

The average number of newspapers for sale in an airport stand is 15. SD is 6.

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C = \frac{6}{15} = 0.4

The average age of the pilots is 36 and SD is 4.

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C = \frac{4}{36} = 0.11

The average age of pilots has a lower coefficient of variation, so it is the most consistent data set.

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