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navik [9.2K]
3 years ago
13

Right Angle Trigonometry

Mathematics
2 answers:
ra1l [238]3 years ago
5 0

Answer:

Step-by-step explanation:

BC/220=sin 60

BC=220 sin 60=220×√3/2=110√3≈190.5 ft

ira [324]3 years ago
4 0

Answer:

190.5 ft

Step-by-step explanation:

For the 60-deg angle, BC is the opposite leg. AB is the hypotenuse.

The trig ratio that relates the opposite leg to the hypotenuse is the sine ratio.

\sin A = \dfrac{opp}{hyp}

\sin 60^\circ = \dfrac{BC}{220}

BC = 220 \sin 60^\circ

BC = 190.5

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AnnZ [28]

Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

7 0
3 years ago
Suppose z is proportional to the square root of x. If z = 717 when x = 9, find the proportionality constant k.??
Dahasolnce [82]

Answer:

  239

Step-by-step explanation:

Write the equation. Fill in the given values, and solve for the unknown,

  z = k√x

  717 = k√9

  k = 717/3 = 239

The constant of proportionality is 239.

8 0
2 years ago
Read 2 more answers
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