'Acceleration' means any change in speed or direction
of motion.
so
C). No acceleration. Straight, at constant speed.
No change of speed or direction.
<u>Answer:</u> The volume of NaOH solution required to reach the half-equivalence point is 0.09 mL
<u>Explanation:</u>
The chemical equation for the dissociation of butanoic acid follows:
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the negative value because concentration cannot be negative
To calculate the volume of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is butanoic acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of NaOH solution required to reach the half-equivalence point is 0.09 mL
I actually do not know the answer can I help tommorow if you are fine with it tooo sleeeepy have 14 exams tommorow have to prepare.
Sorry:(
Answer:- 1500 calories
Solution:- mass of bear = 1.850 g
volume of water = 100.0 mL
Density of water is 1.00 g/moL. So, mass of water would be 100.0 g.
delta T for water = 15.0 degree C
specific heat capacity for water is 1 cal/(g* degree C)
q = m x c x delta T
where, q is the heat energy, m is mass, c is specific heat capacity and delta T is change in temperature.
for water, q = 100.0 x 1 x 15.0
q = 1500 calorie
heat gained by water = heat lost by bear
So, the 1.850 g bear has 1500 cal or 1.50 Cal.
(Where, 1 Cal = 1000 cal)
Answer:
K = 8.1 x 10⁻³
Explanation:
We are told here that these gas phase reactions are both elementary processes, thus the reactions forward and reverse are both first order:
A→B Rate(forward) = k(forward) x [A]
and for
B→A Rate(reverse) = k(reverse) x [B]
At equilibrium we know the rates of the forward and reverse reaction are equal, so
k(forward) x [A] = k(reverse) x [B] for A(g)⇌B(g)
⇒ k(forward) / k(reverse) = [B] / [A] = K
4.7 x 10⁻³ s⁻1 / 5.8 x 10⁻¹ s⁻¹ = 8.1 x 10⁻³ = K
Notice how this answer is logical : the rate of the reverse reaction is greater than the forward reaction ( a factor of approximately 120 times) , and will be expecting a number for the equilibrium constant, K, smaller than one where the reactant concentration, [A], will prevail.
It is worth to mention that this is only valid for reactions which are single, elementary processes and not true for other equilibria.