Answer:- 1500 calories
Solution:- mass of bear = 1.850 g
volume of water = 100.0 mL
Density of water is 1.00 g/moL. So, mass of water would be 100.0 g.
delta T for water = 15.0 degree C
specific heat capacity for water is 1 cal/(g* degree C)
q = m x c x delta T
where, q is the heat energy, m is mass, c is specific heat capacity and delta T is change in temperature.
for water, q = 100.0 x 1 x 15.0
q = 1500 calorie
heat gained by water = heat lost by bear
So, the 1.850 g bear has 1500 cal or 1.50 Cal.
(Where, 1 Cal = 1000 cal)
