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Masja [62]
2 years ago
11

All human body systems works together m. What would happen to someone if one of their systems becomes inefficient?

Chemistry
2 answers:
wariber [46]2 years ago
7 0

Answer:

lol this is what you get for stealing my points

Explanation:

Reil [10]2 years ago
4 0
They would most likely get sick. Or suffer from organ failure. When one part of your body doesn’t work it causes a weakness, making you more susceptible to sicknesses.
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Find the number of moles in 6120 ions of NaCl . Round your answer to two decimal places. Input your answer as 1.03E23, which is
FrozenT [24]

Answer:

Explanation:

NaCl = Na⁺ + Cl⁻

6120 ions of NaCl will contain 3060 ions of Na⁺ and 3060 ions of Cl⁻ , forming 3060 molecules of NaCl .

6.02 x 10²³ molecules of NaCl = 1 mole

3060 molecules of NaCl = 3060 x 10⁻²³ / 6.02 moles

= 508.30 x 10⁻²³ moles

= 5.08 x 10⁻²¹ moles

Answer : 5.08E-21 moles  .

5 0
3 years ago
How many moles are there in 24.00 g of NaCl
Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

               58.5 g of NaCl ------------------- 1 mol

               24.0 g               ------------------- x

                     x = (24 x 1) / 58.5

                     x = 0.41 moles

6 0
3 years ago
G(1)=0 g(n) =g(n-1)+n g(2)=
Aliun [14]
G(2)=2

For this, you can plug in 2 everywhere you see an n. So the equation will read:
g(2)=g(2-1)+2 -> g(2)=g(1)+2. Since we are given g(1)=0, we can plug in 0 where we see g(1). The equation is now. g(2)=0+2. So, g(2)=2.
6 0
3 years ago
A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h
statuscvo [17]

Explanation:

First, calculate the moles of CO_{2} using ideal gas equation as follows.

                PV = nRT

or,          n = \frac{PV}{RT}

                = \frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = \frac{mass}{volume}

Hence, mass of water will be as follows.

                Density = \frac{mass}{volume}

             0.998 g/ml = \frac{mass}{3.26 ml}    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  \frac{3.25 g}{18.02 g/mol}            

                              = 0.180 mol

Moles of hydrogen = 0.180 \times 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  \frac{mass}{12 g/mol}            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  \frac{0.95 g}{16 g/mol}            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_{3}H_{6}O.

Thus, we can conclude that empirical formula of the given compound is C_{3}H_{6}O.            

6 0
3 years ago
PLS HELP ME WITH THESE I WILL MARK U AS BRAINLIEST!!
netineya [11]

Answer:

uy pasagot kung nasagutan mo na pls wala pa akong sagot jan

7 0
3 years ago
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