Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
3 consecutive numbers....x, x + 1 and x + 2
x + x + 1 + x + 2 = 72
3x + 3 = 72
3x = 72 - 3
3x = 69
x = 69/3
x = 23
x + 1 = 23 + 1 = 24
x + 2 = 23 + 2 = 25
so ur numbers are 23,24,25 with 25 being the largest
Answer:
1st one twelve times the sum of a number plus twenty four
Step-by-step explanation:
12f=12xf(whatever number it is)
+
24 ^
twelve l
times
the sum of a number + 24
Answer: Do want to solve it using the quadratic formula because if so the answer is m=7,-2
Step-by-step explanation:
You have to divide the numbers that do not have the variable y in it.
