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GarryVolchara [31]
3 years ago
6

PLEASE HELP PLEASE!!!

Mathematics
1 answer:
defon3 years ago
6 0

Answer:

We conclude that at x = 0 and x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

Therefore, the solution to f(x) = g(x) is:

  • x = -1
  • x - 0

Step-by-step explanation:

Given the table

x                f(x) = 2ˣ - 1                  g(x) = 1/2x

-2                  -3/4                               -1

-1                    -1/2                               -1/2

0                     0                                   0

1                       1                                   1/2

2                     3                                    1

If we carefully observe, we can determine that

at x = 0, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

In other words,

at x = 0

  • f(0) = 0
  • g(0) = 0

Thus,

at x = 0

f(x) = g(x)

Also at x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

In other words,

at x = -1

  • f(-1) = -1/2
  • g(-1) = -1/2

Thus,

at x = -1

f(x) = g(x)

Summary:

Thus, we conclude that at x = 0 and x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

Therefore, the solution to f(x) = g(x) is:

  • x = -1
  • x - 0
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Answer:

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Step-by-step explanation:

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Answer:

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X2 + 45x = -200 using the quadratic formula
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Answer:

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Find the distance between the two points (-5, -2) and T(-3, 4).
Ulleksa [173]

Answer:

\displaystyle d = 2\sqrt{10}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS<u> </u>

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, -2) → x₁ = -5, y₁ = -2

Point (-3, 4) → x₂ = -3, y₂ = 4

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(-3+5)^2+(4+2)^2}
  2. [√Radical] (Parenthesis) Add:                                                                        \displaystyle d = \sqrt{(2)^2+(6)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{4+36}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{40}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{10}
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