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max2010maxim [7]
3 years ago
10

Please help!

Mathematics
1 answer:
Alinara [238K]3 years ago
8 0
The area of the enclosed space is given by the equation
(6+2x)² = 169

We can take the square root of both sides, since 169 is a perfect square:
√(6+2x)² = √169
6 + 2x = 13

Subtract 6 from each side:
6 + 2x - 6 = 13 - 6
2x = 7

Divide both sides by 2:
2x/2 = 7/2
x = 3.5
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Select all the correct answers. Which statements are true about function g? NO LINKS!!!​
Anna35 [415]

Answer:

  A, B, E

Step-by-step explanation:

The attachment shows a graph of the function. It tends to infinity for x going to infinity in either direction. (A, B are true)

The right-side piece is cubic, not quadratic.

The U-shape tells you the function is decreasing on the left side.

The two function definitions have the same value at x=2, so the function has no discontinuities. It is continuous. (E is true)

3 0
2 years ago
Jay earns $5.90 per hour working at the ice cream parlor after school. He needs at least $236 for a stereo system. Choose the in
Studentka2010 [4]
40 hours at 5.90 a hour so 40 hours he would make 236
4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I don't understand how to do this. :'(
natulia [17]

Answer:

Step-by-step explanation:

First and foremost, all quadratics have a domain of all real numbers (as long as we are not given only a portion of the graph, or one with endpoints. Our graph does not have endpoints, so it is assumed that the tails will continue to go down into negative infinity and at the same time, the x coordinates will keep growing as well.) Since our quadratic is upside down, it has a max. That means that none of the values on the graph will be above that point. All the values will be below that highest point (the highest y-value). Y-values indicate range, and since our highest y-value is at y = 2, then the range is

y ≤ 2

3 0
3 years ago
What steps would you use to plot (−3, −4, 0) in a 3-dimensional coordinate system?
eimsori [14]

Answer:

a. From the origin, move back 3 units and down 4 units

Step-by-step explanation:

Given:

The coordinates of a point in a 3-dimensional space is given as:

(-3, -4, 0)

The value of 'x' = -3

The value of 'y' = -4

The value of 'z' = 0

At the origin, the values of 'x', 'y', and 'z' are each equal to 0.

So, the coordinates of origin is (0, 0, 0). In order to reach the point (-3, -4, 0) from the point (0, 0, 0), we don't move along the z-axis as the 'z' value remains the same. We need to move along the 'x' and 'y' directions only.

Now, 'x' is equal to -3. Negative values of 'x' occur backwards from origin. So, we move back by 3 units. to reach the point (-3, 0).

Now, the value of 'y' is -4. Negative values of 'y' occur below the origin. So, we move down by 4 units to reach the point (-3, -4).

Therefore, the correct option is option (a)

A graph in 2 dimensional is shown in support of the answer.

8 0
3 years ago
If x+1/x=7,find x^2+1/x^2​
trapecia [35]

Answer:

x²+1/x² = 51

Explanation:

Given x - 1/x = 7 ---(1)

We know the algebraic identity:

a²+b²-2ab = (a-b)²

Or

a²+b² = (a-b)²+2ab

Now,

x²+1/x²

= (x-1/x)²+2*x*(1/x)

= (x-1/x)²+2

:7²+2 [ from (1)] =

= 49+2

= 51

Therefore,

x²+1/x² = 51

3 0
3 years ago
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