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3 years ago

PLEASE HELP

Mathematics

1 answer:

kotykmax [81]3 years ago

4 0

Answer:66.5 degrees

Step-by-step explanation:

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The quantity of 10 more than d multiplied by 5

elena-s [515]

Answer:

(10 + D)x 5

Step-by-step explanation:

If youre looking for an equation, here it is!

10 more would ba addition (adding to D) and then multiplication by 5.

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4 years ago

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Round 61.062 to one decimal place.

Olegator [25]

Answer: 61.1

Step-by-step explanation: The answer would be 61.1 because .062 is greater than .05, which means that it rounds up.

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3 years ago

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A plumber charges $15 for transportation and $40 per hour for repairs complete the expression that can be used to find the cost

qwelly [4]

Answer:

y = 45x + 15

Step-by-step explanation:

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3 years ago

the building is 1050 feet tall.sally built a scale model of the building .how tall is the model if she used the scale 1 centimet

goldenfox [79]

30 centimeters.

1050 divided by 35 = 30.

4 0

3 years ago

Find area of the shaded region.

Monica [59]

Answer:

The area of the shaded region is about 38.1 square centimeters.

Step-by-step explanation:

We want to find the area of the shaded region.

To do so, we can first find the area of the sector and then subtract the area of the triangle from the sector.

The given circle has a radius of 6 cm.

And the given sector has a central angle of 150°.

The area for a sector is given by the formula:

$\displaystyle A=\pi r^2\cdot \frac{\theta}{360^\circ}$

In this case, r = 6 and θ = 150°. Hence, the area of the sector is:

$\displaystyle \begin{aligned}A&=\pi(6)^2\cdot \frac{150}{360}\\ &=36\pi\cdot \frac{5}{12}\\&=3\pi \cdot 5\\&=15\pi \text{ cm}^2\end{aligned}$

Now, we can find the area of the triangle. We can use an alternative formula:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

Where a and b are the side lengths, and C is the angle between them.

Both side lengths of the triangle are the radii of the circle. So, both side lengths are 6.

And the angle C is 150°. Hence, the area of the triangle is:

$\displaystyle A=\frac{1}{2}(6)(6)\sin(150)=18\sin(150)$

The area of the shaded region is equivalent to the sector minus the triangle:

$A_{\text{shaded}}=A_{\text{sector}}-A_{\text{triangle}}$

Therefore:

$A_{\text{shaded}}=15\pi -18\sin(150)$

Use a calculator:

$A_{\text{shaded}}=38.1238...\approx 38.1\text{ cm}^2$

The area of the shaded region is about 38.1 square centimeters.

6 0

3 years ago