Question

A new star has been discovered that has a peak electromagnetic wavelength of 400.00 nm. What is the star's surface temperature?

Answer 1

As per Wein's displacement law

the peak intensity wavelength is related to its temperature

it is given by relation

$\lambda = \frac{b}{T}$

here given that

$\lambda = 400 nm$

$b = 2.89 * 10^{-3}$

now from above formula

$400 * 10^{-9} = \frac{2.89 * 10^{-3}}{T}$

$T = \frac{2.89 * 10^{-3}}{400 * 10^{-9}}$

$T = 7225 K$

so temperature of the star will be 7225 Kelvin