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3 years ago

If a 3.1 kg ring of granite decreases in temperature 17.9C. What is the

Physics

1 answer:

steposvetlana [31]3 years ago

6 0

I think it’s C but I’m not sure:/

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a pine raft (density = 373 kg/m^3) has a volume of 1.43 m^3. How much of the raft's volume is below the water line? Unit is m^3

Slav-nsk [51]

Answer: 0.5334

Explanation:

i got it right on accellus :p

7 0

3 years ago

The direction of centripetal force is away from the axis of rotation.

Arada [10]

I’m pretty sure it’s true x

4 0

3 years ago

Read 2 more answers

A force of 44 N will stretch a rubber band 88 cm (0.080.08 m). Assuming that Hooke's law applies, how far will aa 11-N forc

Setler79 [48]

Answer:

The rubber band will be stretched 0.02 m.

The work done in stretching is 0.11 J.

Explanation:

Force 1 = 44 N

extension of rubber band = 0.080 m

Force 2 = 11 N

extension = ?

According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.

F = ke

where k = constant of elasticity

e = extension of the material

F = force applied.

For the first case,

44 = 0.080K

K = 44/0.080 = 550 N/m

For the second situation involving the same rubber band

Force = 11 N

e = 550 N/m

11 = 550e

extension e = 11/550 = 0.02 m

The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch. This is in line with energy conservation.

potential energy stored = $\frac{1}{2}ke^{2}$

==> $\frac{1}{2}* 550* 0.02^{2}$ = 0.11 J

3 0

3 years ago

When a piece of copper is taken to the moon , a change will be observed in it's ?

SpyIntel [72]

Weight. Because there is less gravity on the moon.

3 0

3 years ago

Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling witho

8090 [49]

Answer:

Hoop will reach the maximum height

Explanation:

let the mass and radius of solid ball, solid disk and hoop be m and r (all have same radius and mass)

They all are rolled with similar initial speed v

by the law of conservation of energy we can write

$K_{trans}+K_{rot}= P$

for solid ball

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}$

putting $I_{ball}=\frac{2}{5}mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{ball}= 0.071v^2$

now for solid disk

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}$

putting $I_{ball}=\frac{1}{2}mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{disk}= 0.076v^2$

for hoop

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{hoop}\omega^2= mgh_{hoop}$

putting $I_{hoop}=mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{hook}= 0.10v^2$

clearly from the above calculation we can say that the Hoop will reach the maximum height

5 0

3 years ago