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Juliette [100K]
3 years ago
12

Calculate the force between two small charged spheres having charges of 3×10−7 C and 4×10−7 C placed 20 cm apart.

Physics
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

27 . 10^-7 or 27/1000

Explanation:

We use the Coulomb Law

k = Coloumb Constant

q1 and q2 are the charges

d is the distance between the spheres

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An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0
ohaa [14]

Answer:

The COP of the system is = 4.6

Explanation:

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Higher pressure  = 1.8 M pa

Lower pressure = 0.12 M pa

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COP = \frac{T_{L} }{T_{H} -T_{L}   }

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8 0
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A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?
stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, m_1 = 300\ g = 0.3\ kg

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Mass of the larger cart, m_2 = 2\ kg

Initial speed of the larger cart, u_2=0

After the collision,

Final speed of the smaller cart, v_1=-0.81\ m/s (as its recolis)

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The speed of the large cart after collision.

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Let v_2 is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

m_1u_1+m_2u_2-m_1v_1=m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

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