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2 years ago

14

Pleaseeee help! I don't get this!! Please leave a detailed explanation of how you got your answer!!!

2 answers:

Elanso [62]2 years ago

8 0

There is secretly a rectangle and a square. The rectangle is at the bottom and the square is at the top.

rectangle:
The bottom of the rectangle measures 9cm. The sides measure 2cm; 9x2=18
The rectangle measure 18.

Square:
The top measure 6cm. The side measures 5cm. 5x6=30
So now you add everything together. 30+18=48

You could find the rectangle and the square by just creating a simple line. Some of the numbers don’t matter for example 3cm and 7cm didn’t matter in this situation. Hope this helped!!

lisov135 [29]2 years ago

6 0

Answer:

Step-by-step explanation:

Break down the figure into two shapes.

SHAPE A: The larger one. We can infer the size of the bottom is 6 cm because it's the same size as it's top counterpart. Same goes for the left side, which will have a measure of 7 cm.

SHAPE B: The smaller one. We're going to use the same method as we did with the first one, and infer the lengths of the other sides using the existing ones.

To calculate area, it's length times width.

SHAPE A: Its two side measures are 6 and 7, which equates to 42 cm^2.

SHAPE B: Its two side measures are 2 and 3, which equates to 6 cm^2.

If you add the two, the total area is 44 cm^2.

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$20 haircut ; 10% tip

Trava [24]

Answer:

22 dollars

Step-by-step explanation:

10% of $20= 2

20+2=$22

3 0

3 years ago

Write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3

kirill115 [55]

Answer:

f(x) = $x^{4}$ + 2x³ - 4x² - 6x + 3

Step-by-step explanation:

Note that radical zeros occur in conjugate pairs, thus

- 1 + $\sqrt{2}$ is a zero then - 1 - $\sqrt{2}$ is also a zero

$\sqrt{3}$ is a zero then - $\sqrt{3}$ is also a zero

Thus the corresponding factors are

(x - (- 1 + $\sqrt{2}$ ) ), (x - (- 1 - $\sqrt{2}$ ) ), (x - $\sqrt{3}$ ), (x - (- $\sqrt{3}$ )), that is

(x + 1 - $\sqrt{2}$ ), (x + 1 + $\sqrt{2}$ ), (x - $\sqrt{3}$ ), (x + $\sqrt{3}$ )

The polynomial is then the product of the roots

f(x) = (x + 1 - $\sqrt{2}$ )(x + 1 + $\sqrt{2}$ )(x - $\sqrt{3}$ )(x + $\sqrt{3}$ )

= ((x + 1)² - ( $\sqrt{2}$ )²)((x² - ( $\sqrt{3}$ )²)

= (x² + 2x + 1 - 2)(x² - 3)

= (x² + 2x - 1)(x² - 3) ← distribute

= $x^{4}$ - 3x² + 2x³ - 6x - x² + 3

= $x^{4}$ + 2x³ - 4x² - 6x + 3

6 0

3 years ago

HELP ASAP please help I’ll mark as a brnlist

Mariana [72]

Answer:

Step-by-step explanation:

perpendicular (P) = 6

base (b) = 8

hypotenuse (h) =?

we know by using Pythagoras theorem,

h = $\sqrt{(p)^{2} + (b)^{2} } \\$

= $\sqrt{(6)^{2} + (8)^{2} } \\$

= 10

5 0

3 years ago

1. (x^3 - 9 x^2 + 26 x - 24) ÷ (x - 4)

kkurt [141]

Answer:

1. = x^2 -5x+6

Step-by-step explanation:

2. = 2x^2 +5x+3

3. =2x^2 +(x-1) +((x)/x^2 -x+6)

5 0

3 years ago

Find the radius of a circle with an area of 380 in².

Likurg_2 [28]

Answer:

11 inches

Step-by-step explanation:

The area of a circle can be found using:

$a=\pi r^{2}$

We already know that the area is 380, so we can substitute 380 in for a.

380= $\pi r^2$

Now, we need to find the radius. To do this, we need to get r by itself

First, divide both sides by pi

$380/\pi =\pi r^2/\pi$

120.95775675=r^2

Since r is being squared, we need to take the square root of both sides

$\sqrt{120.95775675}=\sqrt{r^2}$

10.9980796846=r

If we round to nearest whole number, our radius is 11 inches

5 0

3 years ago