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svet-max [94.6K]
3 years ago
8

Converting forestland to urban areas through urban development could lead to which of the following? A. Less land available for

lumber production. B. Reduced demand for trees. C. Reduced lumber prices. D. Less costly ways of growing trees.
Chemistry
2 answers:
ahrayia [7]3 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

Conversion of forestland into urban areas requires the cutting of large number of trees so that more land could be available for the urban area.

This cutting of trees will result into reduced demand for trees. Therefore, there will be less land available for lumber production.

Thus, we can conclude that option (a) is the correct answer.

geniusboy [140]3 years ago
3 0
The answer for APEX is A. Less land available for lumber production 
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Answer: D and A

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Why does land heat up more faster than water?
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A sample of tin (Cp = 0. 227 J/g•°C) is placed in a freezer. Its temperature decreases from 15. 0°C to â’10. 0°C as it rele
pshichka [43]

Taking into account the definition of calorimetry, the mass of the sample is 478.41 grams.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q= -543 J because the energy is releases
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  • m= ?
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Replacing:

-543 J= 0.227 \frac{J}{gC}× m× (-5 C)

Solving:

m=\frac{-543 J}{0.227 \frac{J}{gC}x(-5 C)}

<u><em>m=478.41 grams</em></u>

In summary, the mass of the sample is 478.41 grams.

Learn more about calorimetry:

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3 years ago
A solar heating specialist is considering paraffin (Cp = 2.90 J/g O C) as a storage material for heat. How many kg of paraffin w
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Answer:

Mass of paraffin that would be needed to collect the amount of energy as 4.73 x 10³ kg of water is 6.85 * 10³ kg

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Specific heat capacity of paraffin, Cp = 2.90 J/g.°C = 2900 J/kg.°C

Specific heat capacity of water = 4.20 J/g.°C = 4200 J/kg.°C

Amount of heat energy that can be stored by 4.73 * 10³ kg of water heated through a degree rise in temperature can be calculated as below:

Using  H = mCpθ where m is mass of substance, Cp is specific heat capacity and θ is temperature change

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Mass of paraffin that would be needed to collect the amount of energy as 4.73 x 10 3 kg of water for a degree rise in temperature is calculated as follows:

H = mCpθ

19866000J = m * 2900 J/kg.°C * 1°C

m = 19866000J / 2900 J/kg

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Therefore, mass of paraffin that would be needed to collect the amount of energy as 4.73 x 10³ kg of water is 6.85 * 10³ kg

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