Answer:
The balanced single displacement reaction between aluminum and copper sulphate is as follows.

Explanation:
The given ions are as follows.
- Aluminium ion and copper sulfate ion.
Single displacement reaction occurs one element replaces another element.
Hence, the balanced chemical reaction is as follows.

<u>Oxidation half reaction:</u>

Aluminium loses three electrons.
<u>Reduction half reaction:</u>
<u>
</u>
Copper gain three electrons.
Considering the reaction of hydrogen and oxygen to produce water. If 24.6 g of water is produced and 2.9 g of hydrogen is used, the amount of oxygen needed is 21.87 grams
The best way to solve this question is to write out the reaction between hydrogen and oxygen that resulted in the formation of water.
So, we have:

From the above reaction;
2 moles of hydrogen gas reacted with 1 mole of oxygen to produce 2 moles of water.
If;
- 1 mole of O₂ = 32 grams of O₂
- 2 mole of H₂O = 2 × 18 grams of H₂O
- 2 mole of H₂O = 36 grams of H₂O
We can deduce that since 1 mole of O₂ produced 2 moles of H₂O;
Thus, 32 grams of O₂ is needed to produce 36 grams of H₂O.
∴
To produce, 24.6 grams of H₂O, we have:

= 21.87 grams of oxygen.
Therefore, we can conclude that the amount of oxygen needed is 21.87 grams.
Learn more about chemical reactions here:
brainly.com/question/1689737?referrer=searchResults
Answer; NO is the compound Nitrous Oxide whereas No is the metal Nobelium.
Explanation:
Answer:
4.76×10¯⁵ cm
Explanation:
We'll begin by converting 476 nm to m. This can be obtained as follow:
1 nm = 1×10¯⁹ m
Therefore,
476 nm = 476 nm × 1×10¯⁹ m / 1 nm
476 nm = 4.76×10¯⁷ m
Finally, we shall convert 4.76×10¯⁷ m to cm. This can be obtained as follow:
1 m = 100 cm
Therefore,
4.76×10¯⁷ m = 4.76×10¯⁷ m × 100 cm / 1 m
4.76×10¯⁷ m = 4.76×10¯⁵ cm
Thus,
476 nm = 4.76×10¯⁵ cm
Answer:
Option A. 1 0n
Explanation:
Details on how to balanced the equation for the reaction given in the question above can be found in the attached photo.