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umka21 [38]
3 years ago
14

unknown substance's mass: 75.0g, unknown substances molar mass = 150.0 g/mol, Hfus = 5.0x10^3 J/mol, Hvap = 1.00 x 10^4 J/mol, u

nknown substance's specific heat (liquid) = 2.2 J/g, unknown substance's specific heat (gas) = 4.8 J/g, unknown substances's specific heat (solid) = 5.0 J/g; Calculate the amount of heat (in J) for the unkown sample as it is heated at a constant rate from 10.0c to 25.0c as it passes through each of the following regions: region uv
Chemistry
2 answers:
Dimas [21]3 years ago
6 0

Answer:

kkajqjjqjqjnqnqnqjqjq

Leni [432]3 years ago
4 0
These are the answers hope this helps

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A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

7 0
3 years ago
Nitrogen has an average atomic mass of 14.00674. it has two isotopes, n-14 and n-15, with atomic masses of 14.0031 amu and 15.00
masya89 [10]
In this case, we are going to assume that there are 100 atoms to make things easier. 

Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%

14.0031*(100-R)% + 15.001 * R%= 14.00674 
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %

14.0031*(100-R) + 15.001 * R= 14.00674 
1400.31-14.0031R+15.001R=1400.674
0.9979R=0.364
R=0.3648

Then, the abundance of n-15 is 0.3648%

5 0
3 years ago
All phosphorus atoms have the same
svetoff [14.1K]
All phosphorus atoms have the same atomic number. Hope i helped
5 0
4 years ago
Which element has a higher first ionization energy than chlorine (Cl)?
4vir4ik [10]

Answer:

Argon

Explanation:

It has more electron than chlorine

6 0
3 years ago
Read 2 more answers
Bantu donggg <br> Aku butuh banget <br> Makasih.....
mario62 [17]
3? Hope this helps :)
8 0
3 years ago
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