Answer:
The answer is below
Explanation:
i) Since the length of the second clock (radius) is 14 cm = 0.14 m, the distance covered by the second hand in one revelution is:
Distance covered = 2πr = 2π(0.14) = 0.88 m
The time taking to complete one revolution = 60 seconds, hence;
Speed = distance covered in one revolution / time take o complete a revolution
Speed = 0.88 m / 60 s = 0.0147 m/s
ii) Distance covered in 150 s = speed * 150 s = 0.0147 * 150 = 2.2 m
iii) Displacement in 150 seconds = distance from initial position to final position
At 150 s, the hand has covered 2 revolutions and moved 30 s. Hence:
Displacement in 150 seconds = speed * 30 s = 0.0147 * 30 = 0.44 m
Answer: The answer is False
Explanation: This is for the one's in apex <>
Answer:
f=15.5 Hz
Explanation:
Let's determine the internal resistance:
![R=\frac{(p*L)}{A}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B%28p%2AL%29%7D%7BA%7D)
ρ = 1.68*10^-8 Ω m
![L=0.060m*4*60 = 14.4m](https://tex.z-dn.net/?f=L%3D0.060m%2A4%2A60%20%3D%2014.4m)
![A=\pi*r^2\\A= \pi*(5.9x10^-4m/2)^2=2.734*10^-7m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%2Ar%5E2%5C%5CA%3D%20%5Cpi%2A%285.9x10%5E-4m%2F2%29%5E2%3D2.734%2A10%5E-7m%5E2)
Ω
Since the bulb is rated at 12.0 V and 25.0 W,
Current
![I=\frac{25W}{12.0v}=2.08 A](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B25W%7D%7B12.0v%7D%3D2.08%20A)
Therefore, voltage drop inside generator =
![V=(2.08 A)*(0.88)=2.35v](https://tex.z-dn.net/?f=V%3D%282.08%20A%29%2A%280.88%29%3D2.35v)
Actual EMF required is
![E_{mf}=12.0v+2.35v=14.35v](https://tex.z-dn.net/?f=E_%7Bmf%7D%3D12.0v%2B2.35v%3D14.35v)
Note that this is an RMS value.
The peak voltage is
![v_{peak}=14.15v*\sqrt{2} =20.29v](https://tex.z-dn.net/?f=v_%7Bpeak%7D%3D14.15v%2A%5Csqrt%7B2%7D%20%3D20.29v)
For a generator, by Faraday's Law,
![E_{(max)}=N*B*A*w](https://tex.z-dn.net/?f=E_%7B%28max%29%7D%3DN%2AB%2AA%2Aw)
*ω
ω![=144.5\frac{rad}{s}](https://tex.z-dn.net/?f=%3D144.5%5Cfrac%7Brad%7D%7Bs%7D)
f=ω/(2π)=
f=144.5 rad/s/(2π)
f=23.001 Hz
The maximum height at which the baseball will reach is given by the formula
<span>Vf^2 - Vo^2 = 2gh </span>
<span>where </span>
<span>Vf = final velocity = 0 (at its peak) </span>
<span>Vo = initial velocity = 22 m/sec (given) </span>
<span>g = acceleration due to gravity = 9.8 m/sec^2 (constant) </span>
<span>h = maximum height attained by the ball </span>
<span>Substituting appropriate values, </span>
<span>0 - (22)^2 = 9(-9.8)h </span>
<span>NOTE the negative sign attached to the acceleration due to gravity. This simply denotes that the ball is slowing down as it goes up. </span>
<span>Solving for "h", </span>
<span>h = 22^2/(2 * 9.8) </span>
<span>h = 24.69 meters </span>
<span>To solve for the time it reaches its maximum height, use the formula </span>
<span>h = VoT -(1/2)(gT^2) </span>
<span>where </span>
<span>T = time for ball to reach maximum height </span>
<span>and all the other terms have been previously defined. </span>
<span>Substituting values, </span>
<span>24.69 = 22T - (1/2)(9.8)T^2 </span>
<span>Rearranging the above, </span>
<span>4.9T^2 - 22T + 24.69 = 0 </span>
<span>Using the quadratic formula, </span>
<span>T = 2.22 seconds </span>
<span>NOTE --- the above is the time for the ball to reach its maximum height. The total time it is in the air is </span>
<span>Total time = 2(2.22) = 4.44 sec.
Hope this helps :) </span>
Problem
<span>Which of these biomes receives the least amount of rainfall every year?
Answer
Tropical Rainforest</span>