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Liula [17]
3 years ago
7

An appliance with a 20.0-2 resistor has a power rating of 15.0 W. Find the maximum current which can flow safely through the app

liance g
Physics
1 answer:
Alenkinab [10]3 years ago
7 0

Q: An appliance with a 20 Ω resistor has a power rating of 15.0 W. Find the maximum current which can flow safely through the appliance g

Answer:

0.866 A

Explanation:

From the question,

P = I²R............................. Equation 1

Where P = power, I = maximum current, R = Resistance.

Make I the subject of the equation

I = √(P/R).................... Equation 2

Given: P = 15 W, R = 20 Ω

Substitute these values into equation 2

I = √(15/20)

I = √(0.75)

I = 0.866 A

Hence the maximum current that can flow safely through the appliance = 0.866 A

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4 years ago
Which configuration is common to the outer shells of the elements neon, argon, and krypton?
Alexandra [31]
Answer: S2P6

The electronic configuraiton of given elements are as follows:

Ne =<span><span><span>[<span>He</span><span>]2</span></span><span>s2 2</span><span>p6<span>
</span></span></span>Ar = </span><span><span><span>[<span>Ne</span><span>]3</span></span><span>s2 3</span><span>p6<span>
</span></span></span>Kr = </span><span><span>[<span>Ar</span><span>]4</span></span><span>s2 3</span><span>d10 4</span>p6</span>

As it can be seen that for all three elements, their outermost orbital are completely filled, that is it has both s orbital, p orbital and d orbital fulfilled. Noble or inert gas atoms like Neon, Argon, Krypton have fulfilled valence shell. Fulfilled outermost orbital is the most stable electronic state, hence all elements tends to achieve such stability. These noble gas elements are called inert gas because of their fulfilled outermost shell. This means they don't react easily or take part in eletron donating, receiving or sharing. This is because, for all other elements except inert gas atoms, their valence shell is incomplete and they tend to react by other atoms so as to complete their outermost shell , which we call as duplet (in case of Helium like) or Octet state. Such elements either donate some electrons or receive some to acheive such stable state..

5 0
3 years ago
A 330 kg piano slides 3.6 m down a 28o incline and is kept from accelerating by a man who is pushing back on it parallel to the
e-lub [12.9K]

Answer:

a. 652.68N

b. -2349.65J

c. -3116.12J

d. 5465.77J

e. Zero

Explanation:

a. According to equilibrium of forces, the force of gravity is equal to the sum of the frictional force and force exerted by the man in the opposite direction (since they're both resistant forces).

Fg = Fm + Fr

Fm = Fg - Fr

Fm = mgsin(28°) - umgcos(28°)

u = coefficient of frictional force.

Fm = 330*9.8*sin28 - 0.4*330*9.8*cos28

Fm = 1518.27 - 865.59

Fm = 652.68N

b. Work done by man is:

Wm = -Fm * d

Wm = -652.68 * 3.6

Wm = -2349.65J

c. Work done by friction force:

W(Fr) = -Fr * d

W(Fr) = -865.59 * 3.6

W(Fr) = -3116.12J

d. Work done by gravity:

Wg = Fg * d

Wg = 1518.27 * 3. 6

Wg = 5465.77J

e. Net work done on the piano is:

Work done by friction + work done by gravity + work done by man

= -3116.12 + 5464.77 + (-2349.65)

= 0J

7 0
3 years ago
A sample of polonium-210 was left for 414 days.
jenyasd209 [6]

Answer:

PO(1) = PO(0) / 2       1 refers to 1 half life of PO(0)

PO(2) = PO(1) / 2 = P(0) / 4        amount of PO left after 2 half-lives

PO(3) = PO(2) / 2 = PO(0) / 8     amount of PO left after 3 half-lives

414 da / 138 da = 3       3 half-lives pass in 414 da

PO(0) = 8 PO(3) = 8 * 1.45E-4 g = 1.16E-3 g = .00116 g  after 414 days        

6 0
3 years ago
If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number
Misha Larkins [42]

Answer:

the question is incomplete, here is the complete question.

"On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?

1.09 atm

Explanation:

the question addresses an ideal gas. where the relationship between the volume(v),pressure(p),temperature(T) and nos of molecules(n) is expressed as

PV=nRT\\

Where R us the ideal gas constant.

From the question,the number of molecules,volume are constant, we can now re-write the equation as

       P=KT\\

where pressure and temperature are the only varying parameters.

if we vary the constant K we arrive at

\frac{P_{1} }{T_{1}}=\frac{P_{1} }{T_{1}}=...=\frac{P_{n} }{T_{N}}\\

since  the Temprature must be in absolute temperature, we add 273k to it Celsius value.

T_{1} =12+273=285k\\T_{2} =37+273=310k\\P_{1} =1 atm\\

Substituting value into the generated equation, we have

P_{2}=\frac{310*1}{285} \\P_{2}=1.09 atm.\\

7 0
3 years ago
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