1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liula [17]
3 years ago
7

An appliance with a 20.0-2 resistor has a power rating of 15.0 W. Find the maximum current which can flow safely through the app

liance g
Physics
1 answer:
Alenkinab [10]3 years ago
7 0

Q: An appliance with a 20 Ω resistor has a power rating of 15.0 W. Find the maximum current which can flow safely through the appliance g

Answer:

0.866 A

Explanation:

From the question,

P = I²R............................. Equation 1

Where P = power, I = maximum current, R = Resistance.

Make I the subject of the equation

I = √(P/R).................... Equation 2

Given: P = 15 W, R = 20 Ω

Substitute these values into equation 2

I = √(15/20)

I = √(0.75)

I = 0.866 A

Hence the maximum current that can flow safely through the appliance = 0.866 A

You might be interested in
A cyclist reaches the top of a hill with
rjkz [21]

Answer:Based on the excerpt, which best describes Harburg’s view of the Great Depression?

He has no interest in financial success for himself.

He values artistic success over financial success for himself.

He believes most people benefited from losing their financial stability.

He regrets the fact that he gave away his money to benefit his art.

Explanation:

5 0
2 years ago
A race car accelerates from 16.5 m/s to 45.1 m/s in 2.27 seconds. Determine the acceleration of the car.
ioda

Answer:

12.6

Explanation:

4 0
3 years ago
To do work, this truck uses energy stored in chemical
GREYUIT [131]

800 J Got it right on edgenuity

4 0
3 years ago
To test the hypothesis that the population mean mu=3. 6, a sample size n=14 yields a sample mean 4. 007 and sample standard devi
PolarNik [594]

The P value for the given data set is 25127. For finding P value, we have to must find the Z value.

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

The Z value is calculated as;

Z = \dfrac{X - \mu}{\sigma})

Z = (X - μ) / σ

Z = (4.007 - 3.6) / 0.607

Z = 0.67051

The P value for the given data set is 25127.

Learn more about z-score here:

brainly.com/question/21262765

#SPJ1

5 0
2 years ago
BEST ANSWER GET BRAINLEIST!!!!!!!!!!!!!!! PLEASE HELP ASAP!!!!!!!!!!!!!!
ozzi
No person shall be judged by their financial status in the process of applying for a job or position of power in the government.
6 0
3 years ago
Other questions:
  • What are the chemical properties of elements related to?
    12·1 answer
  • The power dissipated in each of two resistors is the same. The current across resistor A is triple that across resistor B. If th
    10·1 answer
  • (3.8 * 10^-2 cm) * (4.4 * 10^-2 cm) * (7.5 * 10^2 cm)
    12·1 answer
  • What is the net force on a 2-kg skateboard accelerating at a rate of 2 m/s2?
    6·1 answer
  • 7. Water flows trough a horizontal tube of diameter 2.5 cm that is joined to a second horizontal tube of diameter 1.2 cm. The pr
    13·1 answer
  • cameron drives his car 15 km north. He stops for lunch and then drives 12 km south. What is his displacement?
    6·1 answer
  • Elias stretches a rubber band and let's it go. The rubber band flies across the room. Elias says this demonstrates the transform
    11·1 answer
  • Unlike the news media, which may be biased, science reporting can be depended on to be objective and not influenced by governmen
    10·1 answer
  • Complete the steps for converting 3.6 gallons per minute to milliliters per second. (1 gallon = 3.79 liters and 1 liter = 1,000
    5·1 answer
  • If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!