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3 years ago

Which of these is an example of acceleration ?

Physics

2 answers:

anygoal [31]3 years ago

8 0

Answer:

no picture or anything so cant anwser

Explanation:

charle [14.2K]3 years ago

5 0

Answer:

can’t answer there’s no picture or options

Explanation:

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The energy band gap of GaAs is 1.4 eV. Calculate the optimum wavelength of light for

notsponge [240]

Answer:

The optimum wavelength = (8.863 × 10⁻⁷) m = 886.3 nm

Explanation:

The light that will generate the photovoltaic energy of 1.4 eV will must have that amount of energy

Energy of light waves is given as

E = hf

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = Frequency of the light

The frequency is then further given as

f = (c/λ)

c = speed of light = (3.0 × 10⁸) m/s

λ = wavelength of the light = ?

E = (hc/λ)

λ = (hc/E)

Energy = E = 1.4 eV = 1.4 × 1.602 × 10⁻¹⁹ = (2.2428 × 10⁻¹⁹) J

λ = (6.626 × 10⁻³⁴ × 3.0 × 10⁸)/(2.2428 × 10⁻¹⁹)

λ = (8.863 × 10⁻⁷) m = 886 nm

Hope this Helps!!!

3 0

3 years ago

A 50 kilogram woman wearing a seatbelt is traveling in a car that is moving with a velocity of +10 meters per second. In an emer

ra1l [238]

Answer:

the answer is A.) -1 * 10^3[N]

Explanation:

The solution consists of two steps, the first step is using the following kinematic equation:

$v=v_{i} +a*t\\where:\\v=final velocity [m/s]\\v_{i}=initial velocity [m/s]\\a=acceleration[m/^2]\\t=time[s]\\$

The initial velocity is 10 [m/s], and the final velocity is zero because the car stops in 0.5[s].

Replacing:

$0=10+a*(0.5)\\a=-20[m/s^2]$

Now in the second part, we need to use the second law of Newton, this law relates the forces with the acceleration of a body.

In the moment when the car stops suddenly the driver will feel the force of the seatbelt acting in the opposite direction of the movement.

$F=m*a\\F=50[kg]*(-20[m/s^2])\\units\[kg]*[m/s^2]=[N]\\F=-1000[N] or -1*10^{3} [N]$

The minus sign means that the force is acting in the opposite direction of the movement.

7 0

3 years ago

Red light has a wavelength of (7. 21x10^7)m. What is the frequency of this light?

Flura [38]

Answer:

TO answer this question i need wave speed

Explanation:

4 0

2 years ago

39. I also use it when I do the homework. (par 1 line 3).

Yuri [45]

Answer:

Explanation:

4 0

2 years ago

Read 2 more answers

In a semiclassical model of the hydrogen atom, the electron orbits the proton at a distance of 0.053 nm. Part A What is the elec

Bezzdna [24]

Answer with Explanation:

We are given that

$r=0.053 nm=0.053\times 10^{-9} m$

$1 nm=10^{-9} m$

Charge on proton,q= $1.6\times 10^{-19} C$

a.We have to find the electric potential of the proton at the position of the electron.

We know that the electric potential

$V=\frac{kq}{r}$

Where $k=9\times 10^9$

$V=\frac{9\times 10^9\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}$

$V=27.17 V$

B.Potential energy of electron,U= $\frac{kq_e q_p}{r}$

Where

$q_e=-1.6\times 10^{-19} c=$ Charge on electron

$q_p=q=1.6\times 10^{-19} C$ =Charge on proton

Using the formula

$U=\frac{9\times 10^9\times (-1.6\times 10^{-19}\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}$

$U=-4.35\times 10^{-18} J$

8 0

3 years ago