Answer:
Explanation:
A )
Magnetic field due to a long wire
B = (μ₀ / 4 π ) x( 2i / r )
= 10⁻⁷ x 2 i / r
where i is current , r is distance of point from the wire
Magnetic field at a point in between the wire will be total of magnetic field generated by both the wires
= 10⁻⁷ [ ( 2 x 2.2 / .009 - 2 x 2.2 / .009 ) ]
= 0
The magnetic field acts in opposite direction so they cancel out each other .
B )
At this point their magnetic field will add up
Net magnetic field
= 10⁻⁷ [ ( 2 x 2.2 / .018 + 2 x 2.2 / .036 ) ]
= 10⁻⁷ [ ( 244.44 + 122.22 ) ]
= 10⁻⁷ x 366.66
= 366.66 x 10⁻⁷ T .
C ) Force on a wire in a magnetic field = BiL where B is magnetic field , i is current and L is length of the wire . If length is one then
force = Bi
magnetic field on each wire
= B = (μ₀ / 4 π ) x( 2i / r )
= 10⁻⁷ x 2 x 2.2 / .018
= 244.44 x 10⁻⁷ T
force on each per unit length
= Bi
= 244.44 x 10⁻⁷ x 2.2
= 537.77 x 10⁻⁷ N /m
This is force of interaction between the two wires . Since direction of current is same , they will attract each other .
Answer:
The net outward force is exerted on a square window of the house is 
.
Explanation:
Given that,
Pressure = 1.02 atm
External air pressure = 0.910 atm
Distance = 2.03 m
We need to calculate the net outward force
Using formula of force
Where, P = pressure
F = force
A = area
Put the value into the formula
Hence, The net outward force is exerted on a square window of the house is .
Answer:
Solution given:
frequency[f]=60,500,000Hz
velocity[V]=300,000,000m/s
wave length=?
we have
wave length=
=
=
=4.96 m
Option A.4.96m
Let's assume that the gas is behaving ideally. Hence, we can use the ideal gas equation: PV = nRT. We only know the value of the volume. Since it was not mentioned, let's assume that the temperature at those altitude do not have a significant difference. So, we can assume temperature, as well as the number of moles is constant, because it is a closed system. The other parameter, pressure, can be calculated in terms of height:
P = ρgh, where ρ is the air density equal to 0.0765 lb/ft³, g is the acceleration due to gravity equal to 32.2 ft/s², and h is the height in feet. Let's solve for the pressure, P₁.
P₁ = ( 0.0765 lb/ft³)(32.2 ft/s²)(99 feet) = 243.8667 lb/ft-s²
For consistency, let's convert V₁ to ft³ using the conversion 12 inches=1 foot.
V₁ = (6 in³)(1 foot/12 inches)³ = 0.003472 ft³
Then, let's use this to find nRT.
P₁V₁ = nRT
nRT = (243.8667 lb/ft-s²)(0.003472 ft³)
nRT = 0.8467 lb-ft²/s²
Now, let's do the same procedure for P₂:
P₂ = ( 0.0765 lb/ft³)(32.2 ft/s²)(33 feet) = 81.2889 lb/ft-s²
Then, we use the ideal gas equation knowing that nRT=0.8467
P₂V₂ = nRT = 0.8467 lb-ft²/s²
81.2889 lb/ft-s²(V₂) = 0.8467 lb-ft²/s²
V₂ = 0.010416 ft³
Finally, let's convert this to in³:
V₂ = 0.010416 ft³ (12 in/1ft)³
V₂ = 18 ft³
The signs that there is a chemical reaction are
-color change
-a precipitate (a solid was formed)
