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antiseptic1488 [7]
2 years ago
15

Electromagnets project student guide y’all i need helppppo

Physics
1 answer:
Masja [62]2 years ago
7 0

Answer:

I don't know

Explanation:

you need then search here

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A freight car of mass M contains a mass of sand m. At t = 0 a constant horizontal force F is applied in the direction of rolling
Veronika [31]

Answer:

Amount of linear movement

Explanation:

Our system is defined by the rate of change in mass that

leaves the car \Delta m_ {s} , this happens during a time interval

[t, t + \Delta t], in addition to freight car and sand at time t.

In this way we need to define the two states:

State 1,

consider t, m_ {c} (t) + \Delta m_ {s} and V.

State 2,

consider t + \Delta t, m_ {c} (t), V + V \Delta V

In this state is the mass of sand output, which

is composed of

\Delta m_{s}, V + \Delta V

In this way we define the Linear movement in x, like this:

p_ {x} (t) = (\Delta m_ {s} + m_ {c} (t)) v

p_ {x} (t+\Delta t) = (\Delta m_ {s} + m_ {c} (t)) (v + \Delta v)

m_ {c} (t) = m_ {c, 0} - bt = m_ {c} + m_ {s} -bt

In this way we proceed to obtain the Force

F =\lim_{\Delta t \rightarrow 0} \frac {p_x (t + \Delta t) -p_ {x} (t)} {\Delta t}

F = lim_{\Delta t \rightarrow 0} m_ {c} (t) \frac {\Delta v} {\Delta t} + lim_{\Delta t \rightarrow 0} m_ {s} (t) \frac {\Delta v} {\Delta T}

Since the mass of the second term becomes 0, the same term is eliminated, thus,

F = m_ {c} (t) \frac {dv} {dt}

\int\limit ^ {v (t)} _ {v = 0} dv = \int\limit^t_0 \frac{Fdt} {m_ {c} + m_ {s} -bt}

V (t) = - \frac {F} {b} ln (\frac {m_c + m_s-bt} {m_c + m_s})

3 0
4 years ago
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