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Anuta_ua [19.1K]
3 years ago
15

Two long parallel wires each carry 2.2 A in the same direction, with their centers 1.8 cm apart.A. Find the magnitude of the mag

netic field halfway between the wires.B. Find the magnitude of the magnetic field at a point in the same plane as the wires, 1.8 cm from one wire and 3.6 cm from the other.C. Find the magnitude of the force of interaction (per length) between the wires.
Physics
1 answer:
Butoxors [25]3 years ago
8 0

Answer:

Explanation:

A )

Magnetic field due to a long wire

B = (μ₀ / 4 π ) x( 2i / r )

= 10⁻⁷ x 2 i / r

where i is current , r is distance of point from the wire

Magnetic field at a point in between the wire will be total of magnetic field generated by both the wires

= 10⁻⁷ [ ( 2 x 2.2 / .009 - 2 x 2.2 / .009 ) ]

= 0

The magnetic field acts in opposite direction so they cancel out each other .

B )

At this point their magnetic field will add up

Net magnetic field

=  10⁻⁷ [ ( 2 x 2.2 / .018 + 2 x 2.2 / .036 ) ]

=  10⁻⁷ [ ( 244.44 + 122.22 ) ]

= 10⁻⁷ x 366.66

= 366.66  x 10⁻⁷ T .

C ) Force on a wire in a magnetic field = BiL where B is magnetic field , i is current and L is length of the wire . If length is one then

force = Bi

magnetic field on each wire

= B = (μ₀ / 4 π ) x( 2i / r )

= 10⁻⁷ x 2 x 2.2 / .018

= 244.44 x 10⁻⁷ T

force on each per unit length

= Bi

= 244.44 x 10⁻⁷ x 2.2

= 537.77 x 10⁻⁷ N /m

This is force of interaction between the two wires . Since direction of current is same , they will attract each other .

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Pounds

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3 years ago
Daffy Duck is standing 6.8 m away from Minnie Duck. The attractive gravitational force between them is 5.4x10-8 N. If Daffy Duck
artcher [175]

Answer:

432.78 Kg

Explanation:

From the question given above, the following data were obtained:

Distance apart (r) = 6.8 m

Force of attraction (F) = 5.4×10¯⁸ N

Mass of Daffy Duck (M₁) = 86.5 kg

Mass of Minnie Duck (M₂) =?

NOTE: Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

The mass of Minnie Duck can be obtained as follow:

F = GM₁M₂ / r²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 6.8²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 46.24

Cross multiply

6.67×10¯¹¹ × 86.5 × M₂ =5.4×10¯⁸ × 46.24

Divide both side by 6.67×10¯¹¹ × 86.5

M₂ = 5.4×10¯⁸ × 46.24 / 6.67×10¯¹¹ × 86.5

M₂ = 432.78 Kg

Therefore, the mass of Minnie Duck is 432.78 Kg

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3 years ago
Neglecting air​ resistance, the distance s left parenthesis t right parenthesis in feet traveled by a freely falling object is g
ivann1987 [24]

Explanation:

It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet

The distance traveled by a freely falling object is given by :

s(t)=16t^2

16t^2=862

t=\sqrt{53.875}

t = 7.34 seconds

So, the object will take 7.34 seconds to fall to the ground from the top of the​ building. Hence, this is the required solution.

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2 years ago
How much energy is needed to change 100 g of 0o C ice to 0o C water? The latent heat of fusion for water L=335,000 J/kg. Hint: T
pychu [463]

Answer:

33.5 kJ

Explanation:

here there is no difference is made in the temperature. Only thing happens here is the conversion of the ice in to water of 0 degree. The heat energy taken from the outside is spent for this conversion.

we have ice 100g =0.1 kg

Appplying Q=mL

                  Q= 0.1 kg * 335 000 J kg^{-1}

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                   Q = 33.5 kJ

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3 years ago
When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the
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Answer:

Given: V=12 V

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Let the resistance be R

By Ohm's Law, 

V=IR

12=2.5×10−3R

R=4.8×103 Ω

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