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3 years ago

Please help! This is due tomorrow and I absolutely need help.

Physics

1 answer:

zysi [14]3 years ago

4 0

Answer:

Correct answer: 11. Total distance d = 200m ; 12. Vav = 3.63m/s ;

13. Total displacement Dt = 0m ; 14. V₂(10s-15s) = 0 m/s ;

15. V₃(15s-40s) = 4 m/s ; 16. V₁(0s-10s) = 6 m/s > V₄(40s-55s) = 2.67 m/s

Explanation:

The whole movement can be divided into four stages.

In the first stage the subject moves 60m in a positive direction for 10s,

in the other it is stationary for 5s, in the third it moves 100m in the opposite (negative) direction for 25s and in the fourth in the positive 40m for 15s.

11. Total distance = 60 + 0 + 100 + 40 = 200m

12. The formula for calculating the average speed (velocity) is

Vav = (S₁ + S₂ + S₃ + S₄) / (t₁ + t₂ + t₃ + t₄)

Vav = (60 + 0 + 100 + 40)/ (10 + 5 + 25 + 15) = 200/55 = 3.63 m/s

13. The movement started from the origin and ended at the origin

Total displacement is zero meters.

14. The speed between 10s and 15s is zero, because he did not move.

15. V₃ = S₃/t₃ = 100/25 = 4 m/s

16. V₁ = S₁/t₁ = 60/10 = 6 m/s and V₄ = S₄/t₄ = 40/15 = 2.67 m/s

V₁ > V₄

God is with you!!!

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4vir4ik [10]

Answer:

Explanation:

F = mω²R

F = 15(2π/8.5)²(7.8)

F = 63.93044788...

F = 63.9 N

answer a) is the closest. No idea how they got a value that low unless they used a poor approximation for π.

4 0

3 years ago

a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car m

padilas [110]

Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

Acceleration is the rate of change of velocity.
It is given by the equation, a = change in velocity/time

Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

Force is calculated by the equation, F = Mass × Acceleration
This is based on Newton's second law of motion.

Here, mass of the car = 1500 kg and a = 3.375 m/s²

⇒ Force = 1500 × 3.375 = 5062.5 N

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3 years ago

A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d. A battery fully charg

Alja [10]

The capacitance of a capacitor of a parallel plate is given by:

$C=\frac{kA\cdot\epsilon_o}{d}$

Where:

$\begin{gathered} \epsilon_o=_{\text{ }}Vacuum_{\text{ }}permittivity \\ k=_{\text{ }}Dielectric_{\text{ }}constant=2 \\ A=_{\text{ }}Area_{\text{ }}of_{\text{ }}the_{\text{ }}plates \\ d=_{\text{ }}distance_{\text{ }}betwen_{\text{ }}the_{\text{ }}plates \end{gathered}$

We also know:

$\begin{gathered} Q=\frac{q}{V} \\ so\colon \\ \frac{q}{V}=\frac{kA\cdot\epsilon_o}{d} \\ V=\frac{qd}{kA\cdot\epsilon_o} \\ if \\ k=2 \\ V=\frac{1}{2}(\frac{qd}{kA\cdot\epsilon_o}) \end{gathered}$

As we can see the voltage halves

And since: