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givi [52]
4 years ago
7

mark has $1,000. he spends $910 on shopping.later he divides all the money into three parts out of which two parts were distribu

ted and one part keeps for himself.then he found $100 on the road.write the final expression and find the money he has left????
Mathematics
2 answers:
Vlada [557]4 years ago
7 0

Answer:

130

Step-by-step explanation:

1,000-910=90÷3=30+100=130 simple

never [62]4 years ago
4 0

Answer: he keeps a total of $130 dollars

assuming he divided his remainder of $90 into 3rds so $30 $30 $30

Step-by-step explanation:

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When counting from 5 what number follows 4
Kryger [21]

Answer:

3 is the answer

Step-by-step explanation:

5.........4............3..............2...............1

so 3 follows 4

4 0
4 years ago
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MANUFACTURING. The cost of manufacturing widgets is given by
nadezda [96]

Let's solve

  • C=2p+35

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2 years ago
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Geometry Special Quadrilaterals show work please
Charra [1.4K]

Answer:

a = 16

w = 125

x = 120

y = 55

Step-by-step explanation:

<u>FINDING 'a'</u>

31 = a + 46 / 2

62 = a + 46

16 = a

<u>FINDING 'w'</u>

* This section looks Non-Isosceles trapezoid so I will be following the rule according it

w + 55 = 180

w = 125

<u>FINDING 'y'</u>

y = 55

- Because of corresponding angles

<u>FINDING 'x'</u>

* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.

x + 60 = 180

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6 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
4 years ago
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Delvig [45]
Let the number be represented by x
2x=60+ 5x                          -20*2=60+5*-20
2x-5x=5x-5x+60                     -40=60+-100
-3x=60                                      -40=-40
-3x/-3=60/-3
x=-20
Therefore the number is -20
5 0
3 years ago
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