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labwork [276]
3 years ago
8

Help me pls Isbaksbaosbvshshs

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

9514 1404 393

Answer:

  3.  84 km

  4.  y = 3/4x

Step-by-step explanation:

3. The map and ground distances can form a proportion:

  ground distance / map distance = 24 km / (2 cm) = x / (7 cm)

Multiplying by 7 cm gives ...

 x = (24 km)(7/2) = 84 km

The actual distance is 84 km.

__

4. We notice that y (9) is less than x (12), so the multiplier of x must be less than 1. The appropriate equation is ...

  y = 3/4x

Jobisdone [24]3 years ago
5 0

Answer:

84

Step-by-step explanation:

The answer is 84. Every 2cm is 24km. 6cm=72 1cm=12

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Which solution to the equation 1/x-1=x-2/2x^2-2 is extraneous?
olga2289 [7]
<span>An extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the original problem.

Given the equation:
\frac{1}{x-1} = \frac{x-2}{2x^2-2}  \\  \\ 2x^2-2=(x-1)(x-2)=x^2-3x+2 \\  \\ x^2+3x-4=0 \\  \\ (x-1)(x+4)=0 \\  \\ x-1=0 \ or \ x+4=0 \\  \\ x=1 \ or \ x=-4

From the equation, it is obtained that x = 1 and x = -4 are the solutions of the equation.

Now, we substitute x = 1 into the equation as follows:
</span><span>\frac{1}{1-1} = \frac{1-2}{2(1)^2-2}  \\  \\  \frac{1}{0} = \frac{-1}{2-2}  \\  \\  \frac{1}{0} = \frac{-1}{0}

As can be see, for x = 1, the equation is undefined.

Now, we substitute x = -4 into the equation as follows:
\frac{1}{-4-1} = \frac{-4-2}{2(-4)^2-2} \\  \\  \frac{1}{-5} = \frac{-6}{2(16)-2} = \frac{-6}{32-2} = \frac{-6}{30} \\  \\ - \frac{1}{5} =- \frac{1}{5}

It can be seen that x = -4 is a valid solution of the orignal equation.

Therefore, x = 1 is an extraneous solution to the equation
\frac{1}{x-1} = \frac{x-2}{2x^2-2}</span>
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