Answer:
M_c = 100.8 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two cases shown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *144
M_c = 2.5*( 42 / 150 ) *144
M_c = 100.8 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.
Answer:
k = 5178.8 N/m
Explanation:
As we know that spring mass system will oscillate at angular frequency given as

now we have

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

here A= maximum compression of the spring
so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

here we know that
v = 85 km/h

now we have


now from above equation of acceleration we have



1. The skater is traveling at 50 mph
2. The biker is traveling at 5 mph
3. The speed of the driver is known as accelerative speed (i dont know if this last one is right but the other 2 should be)
Answer:
4.2 m/s
Explanation:
The velocity-time graph is piecewise linear. The acceleration in each of the three segments of the graph is uniform. The instant lies between and t = 6.0s 100 s, so the acceleration must be calculated using the slope of the middle segment.
a =
(9.6 -2.4)m/s
------------------
(10.0 -6.0)s
= 1.8 m/s2
The instantaneous velocity is to be found after the object accelerates over an interval T = (7.0 - 6.0) s = 1.0 s, starting from a velocity of 2.4 m/s,
So the velocity at t = 7.0 s is
v = u + aT = 2.4 m/s + (1.8 m/s2)(1.0 s) = 4.2 m/s
The exponential growth/decay formula is given by A = Pe^(rt), where A is the final amount, P is the initial amount, r is the rate of growth/decay and t is time.
We are given A = (1/500)P and t=1, so substituting:
(1/500)P = Pe^(r*1)
Cancelling out P on both sides:
1/500 = e^r
ln(1/500) = ln(e^r)
r = -6.215
Rate of decay is -6.215 per day.