All categories

3 years ago

Extremely confused. "Show that the two vectors can be added as a + b or as b + a yet still provide the same resultant.

Physics

1 answer:

jeyben [28]3 years ago

8 0

You can prove this by using the commutative property:

a + b = b + a

basically, as long as they are the same length

a + b = c(resultant vector)

and

b + a = c(resultant vector.

hope this helps

You might be interested in

2)It is known that the connecting rodS exerts on the crankBCa 2.5-kN force directed down andto the left along the centerline ofA

11111nata11111 [884]

Answer:

M_c = 100.8 Nm

Explanation:

Given:

F_a = 2.5 KN

Find:

Determine the moment of this force about C for the two cases shown.

Solution:

- Draw horizontal and vertical vectors at point A.

- Take moments about point C as follows:

M_c = F_a*( 42 / 150 ) *144

M_c = 2.5*( 42 / 150 ) *144

M_c = 100.8 Nm

- We see that the vertical component of force at point A passes through C.

Hence, its moment about C is zero.

5 0

4 years ago

What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ

borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

$\omega = \sqrt{\frac{k}{m}}$

now we have

$\omega = \sqrt{\frac{k}{1200}}$

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

$a = \omega^2 A$

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

$\frac{1}{2}mv^2 = \frac{1}{2}kA^2$

here we know that

v = 85 km/h

$v = 85 \times\frac{1000}{3600} = 23.61 m/s$

now we have

$(1200)(23.61^2) = kA^2$

$A^2 = \frac{6.68 \times 10^5}{k}$

now from above equation of acceleration we have

$5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}$

$5.0(9.81) = \sqrt{k}(0.68)$

$k = 5178.8 N/m$

6 0

4 years ago

1- If a skater travels 50 miles in one hour, what is the skaters speed?

slava [35]

1. The skater is traveling at 50 mph
2. The biker is traveling at 5 mph
3. The speed of the driver is known as accelerative speed (i dont know if this last one is right but the other 2 should be)

6 0

3 years ago

The velocity-time graph of an object moving north-west is shown here. What is the instantaneous velocity of the object at time t

LUCKY_DIMON [66]

Answer:

4.2 m/s

Explanation:

The velocity-time graph is piecewise linear. The acceleration in each of the three segments of the graph is uniform. The instant lies between and t = 6.0s 100 s, so the acceleration must be calculated using the slope of the middle segment.

a =

(9.6 -2.4)m/s

------------------

(10.0 -6.0)s

= 1.8 m/s2

The instantaneous velocity is to be found after the object accelerates over an interval T = (7.0 - 6.0) s = 1.0 s, starting from a velocity of 2.4 m/s,

So the velocity at t = 7.0 s is

v = u + aT = 2.4 m/s + (1.8 m/s2)(1.0 s) = 4.2 m/s

4 0

3 years ago

The concentration of an isotope is 1/500 of its initial value after one day. What is the rate of decay?

mel-nik [20]

The exponential growth/decay formula is given by A = Pe^(rt), where A is the final amount, P is the initial amount, r is the rate of growth/decay and t is time.

We are given A = (1/500)P and t=1, so substituting:
(1/500)P = Pe^(r*1)
Cancelling out P on both sides:
1/500 = e^r
ln(1/500) = ln(e^r)
r = -6.215

Rate of decay is -6.215 per day.

8 0

3 years ago