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Yanka [14]
2 years ago
6

Any object that is given any initial velocity and which follows a path due to gravitational force acting on it and by the fricti

onal resistance of the atmosphere is called?
Physics
1 answer:
amm18122 years ago
5 0

Any object that is given any initial velocity and which follows a path due to gravitational force acting on it and by the frictional resistance of the atmosphere is called a projectile. This is because the object is projected and not influenced by anything except gravity.

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Name three (3) organelles that are found in plant cells that are not commonly found in animal cells?
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Answer:

cell wall, chloroplasts, plastids

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A spring has an unstretched length of 10 cm. it exerts a restoring force f when stretched to a length of 11 cm. part a for what
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13 cm
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If you know the distance an object has traveled in a certain amount of time you can determine
Nutka1998 [239]
With that information, you can determine the object's speed.
Just divide the distance covered by the time to cover the distance.

If you also know the direction the object moved, then you can
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A stone is dropped from a bridge abd it hits the water 2.2 seconds later how high is the bridge above the water
Bess [88]

Answer:

h = 23.716 m

Explanation:

Given that,

The time taken by the stone to hit the water is, t = 2.2 s

Height of the bridge above the ground, h = ?

The distance that the body will fall through the time is given by the formula

                                S = 1/2 gt²  m

Where,        

                              g - acceleration due to gravity

Substituting the values in the above equation

                               S = 1/2 x 9.8 m/s² x (2.2 s)²

                                  = 23.716  m

Therefore, the height of the bridge from the surface of the water is h = 23.716  m

8 0
3 years ago
A circular coil of wire of radius 5.0 cm has 20 turns and carries a current of 2.0 A. The coil lies in a magnetic field of magni
Korvikt [17]

Answer:a. Magnetic dipole moment is 0.3412Am²

b. Torque is zero(0)N.m

Explanation: The magnetic dipole moment U is given as the product of the number of turns n times the current I times the area A

That is,

U = n*I*A

But Area A is given as pi*radius² since it is a circular coil

Radius given is 5cm converting to meter we divide by 100 so we have our radius to be 0.05m. So area A is

A = 3.142*(0.05)² =7.86*EXP {-3} m²

Current I is 2 A

Number of turns is 20

So magnetic dipole moment U is

U = 20*2*7.86*EXP {-3}=0.3142A.m²

b. Torque is given as the cross product of the magnetic field B and magnetic dipole moment U

Torque = B x U =B*U*Sine(theta)

But since the magnetic field is directed parallel to the plane of the coil from the question, it means that the angle between them is zero and sine zero is equals 0(zero) if you substitute that into the formula for torque you will find out that your torque would equals zero(0)N.m

7 0
3 years ago
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