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3 years ago

What is the silica content of magma that has a low viscosity??

2 answers:

8 0

For the answer to the question above, the answer is
low silica content
<span>(basaltic magma)
or should I say the answer is </span>Magma with high viscosity
I hope my answer helped you. Feel free to ask more questions. Have a nice day!

marysya [2.9K]3 years ago

3 0

The viscosity of magma is directly related to the silica content. That being said, the viscosity of magma is higher when the silica content is also high and it is a low viscosity magma when the silica content is also low. The silica content of low viscosity magma is approximately 45 - 55 wt%.

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In the amusement park ride known as Magic Mountain Superman, powerful magnets accelerate a car and its riders from rest to 43.4

Anton [14]

Answer:

Average net force, F = 15157.15 N

Explanation:

It is given that,

The mass of the car and riders is, $m=3\times 10^3\ kg$

Initial speed of the car, u = 0

Final speed of the car, v = 43.4 m/s

Time, t = 8.59 seconds

We need to find the average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :

F = m a

$F=m(\dfrac{v-u}{t})$

$F=3\times 10^3\ kg\times (\dfrac{43.4\ m/s-0}{8.59\ s})$

F = 15157.15 N

So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.

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3 years ago

A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has

Alex777 [14]

Answer:

r = 0.5 m

Explanation:

First we find the angular speed of the ball by using its period:

ω = θ/t

For the time period:

ω = angular speed = ?

θ = angular displacement = 2π rad

t = time period = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.56 rad/s

Now, for the radius:

v = rω

r = v/ω

where,

v = linear speed = 6.29 m/s

r = radius = ?

r = (6.29 m/s)/(12.56 rad/s)

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3 years ago

Which describes the changes in visible light moving from red to violet?

Alexxx [7]

The energy increases

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2 years ago

Dwayne ‘The Rock’ Johnson needs to escape from the fourth floor of a burning building (in a movie). He ties a rope around his wa

ZanzabumX [31]

Answer:

Final Speed of Dwayne 'The Rock' Johnson = 15.812 m/s

Explanation:

Let's start out with finding the force acting downwards because of the mass of 'The Rock':

Dwayne 'The Rock' Johnson: 118kg x 9.81m/s = 1157.58 N

Now the problem also states that the kinetic friction of the desk in this problem is 370 N

Since the pulley is smooth, the weight of Dwayne Johnson being transferred fully, and pulls the desk with a force of 1157.58 N. The frictional force of the desk is resisting this motion by a force of 370 N. Subtracting both forces we get the resultant force on the desk to be: 1157.58 - 370 = 787.58 N

Now lets use F = ma to calculate for the acceleration of the desk:

787.58 = 63 x acceleration

acceleration = 12.501 m/s

Finally, we can use the motion equation:

$v^2 - u^2 = 2*a*s$

here u = 0 m/s (since initial speed of the desk is 0)

a = 12.501 m/s

and s = 10 m

Solving this we get:

$v^2 - 0 = 2 * 12.501 * 10$

$v = 15.812 m/s$

Since the desk and Mr. Dwayne Johnson are connected by a taught rope, they are travelling at the same speed. Thus, Dwayne also travels at 15.812 m/s when the desk reaches the window.

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3 years ago

This problem has been solved!

lana66690 [7]

Answer:

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