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Rufina [12.5K]
3 years ago
12

Given f(x)=-2/3x+3 and g(x)=-2x^2-5

Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

2/3 give 3 with a g(8) 25 real

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What is 63 over 75 as a decimal?
marissa [1.9K]

Answer:

0.84

Step-by-step explanation:

Use a calculator.  That would be 0.84.

                               3*21

Note that 63/75 = ---------- = 21/25.  Multiplying top and bottom by 4 results

                                3/25                   in 0.84 (so this answer checks out ok)

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3 years ago
Four-ninths of the students at Edison Junior High School walk to school. If 248 students walk to school, how many students atten
Gekata [30.6K]

9514 1404 393

Answer:

  558

Step-by-step explanation:

Let p represent the student population at Edison Jr High. Then we know ...

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3 years ago
Math is garbage and it sucks please help before I smash my laptop with a brick
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Answer:

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5 0
3 years ago
Read 2 more answers
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
4 years ago
PLEASE HELP!
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Two-third of the jar is filled with flower
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3 years ago
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