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Troyanec [42]
3 years ago
15

What is the range of a function 2x-1=y if the domain is {-1, 0, 2}?

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0
The answer is the 3rd dot : (-3,-1,3) you just need to plug the values of the domain into the equation to get the range, range are the y values.
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If f(x)=(1/8)(8^x) what is f(3)?<br> A. 1/512<br> B. 1/64<br> C. 512<br> D. 64
cestrela7 [59]
Hi there!

Let's solve this problem step by step!
f(x) =  \frac{1}{8} (8 {}^{x})

To find f(3) we must substitute x = 3 into the formula.
f(3) =  \frac{1}{8} (8 {}^{3} )

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Work out the exponents inside the parenthesis first.
f(3) =  \frac{1}{8}  \times 512

And finally multiply.
f(3) =  \frac{1}{8}  \times  \frac{512}{1}  =  \frac{512}{8}  = 64

Hence, the answer is D. 64.
~ Hope this helps you!
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