3 years ago

9(x +1) +{2y(z -1)}/2 Solve for y How do you do this? I’m confused

1 answer:

8 0

Answer
If only {2y(z-1)} is being divided by two:

9x+9+yz-y

If whole equation is divided by two:

9x+9+2yz-2y over 2

Explanation: In the first instance, you can cancel out the 2 in the numerator and denominator, which leaves you 9(x+1) + {y(z-1)}. You can then simplify to get 9x+9+yz-y

In the second instance, you distribute 9 to what is inside the parentheses, and get 9x+1. You then distribute 2y to what is inside the parentheses within the brackets and get 2yz-2y. You are then left with 9x+9+2yz-2y over 2

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3 years ago

Refer to the attachment and solve

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Answer:

$-8\frac{5}{8}$