I think it can be 605. I'm not sure exactly, but I think it is.
<u>Answer</u>:- No.
<u>Explanation</u> :-
<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>
<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.
<u>Here</u>,
hypotenuse = 12 (as it is the longest side)
and other two sides are 6 and 9.
----> 6^2 + 9^2 = 12^2
----> 36 + 81 = 144
----> 117 = 144
Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.
answer:
y = 2x - 5
work:
to write equations, we use the format y = mx + b.
m stands for the slope, and b stands for the y intercept.
this means that you should be able to enter the values for y and x and get a valid equation as a result.
in this equation, we are not given a y intercept value, but we do have a slope and x and y values, so we have to solve by substituting.
so, let's substitute in the values of y and x and the slope,
and solve for b, the y intercept.
1 = 2(3) + b (multiply 2 x 3)
1 = 6 + b (subtract 6 from both sides)
- 5 = b
b has a value of -5. let's place this into the equation.
y = 2x - 5.
the slope is 2, and the y intercept is -5, let's plug in our y and x values to verify that this is true.
1 = 2(3) - 5
1 = 6 - 5
1 = 1
so, this equation is correct. hope this helps and have a great day!
The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].
Hope this helps.
