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Salsk061 [2.6K]
3 years ago
6

Jen was making cake pops for the bake sale. After 3 hours, she had completed half of the work. She called Maryna for help and to

gether they finished everything in half an hour. How long would it take Maryna to finish the job alone if she replaced Jen after Jen baked for 3 hours? PLS HELP!!!!!!!!
Mathematics
1 answer:
Inga [223]3 years ago
3 0

Answer:

0.6 hours

Step-by-step explanation:

Let's say J is Jen's speed (cake pops per hour), and let's say M is Maryna's speed (cake pops per hour).

Let's say there are 12 cake pops total that need to be made.  Jen made half of the cake pops in 3 hours, so she made 6 cake pops in 3 hours.  So her speed is 2 cake pops per hour.

Then, Jen and Maryna made the other half of the cake pops in 1/2 hour.  Therefore, their combined speed is:

J + M = 6 cake pops / (1/2 hr)

J + M = 12

2 + M = 12

M = 10

So Maryna can make 10 cake pops per hour.

If Maryna was working alone, the amount of time it would take her to make 6 cake pops is:

6 cake pops / (10 cake pops per hour) = 0.6 hours

It would take 0.6 hours, or 36 minutes.

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Casey is six times as old as Ralph. In two years, she will be four times as old as Ralph. How old is each of them now?
lisov135 [29]

Ralph is 3 years old

Casey is 18 years old

Step-by-step explanation:

Let the age of Ralph be x

Then Casey is 6 times as old as Ralph will be 6x

In two years

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Equate the two equations for Casey as

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Current age;

Ralph= x= 3 years old

Casey=6x = 6*3= 18 years

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Karo-lina-s [1.5K]

Answer:

∠L = 43°

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∠N = 16°

Step-by-step explanation:

<u>Start by setting all sides equal to 180</u>

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11x + 4 = 180

      - 4     - 4

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