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3 years ago

Based on the location of the original figure, in which quadrant will the figure be after rotating it

1 answer:

5 0

I am sorry but I can't answer this without a diagram of where this figure is and what quadrant will the figure be after rotating it.

SRY :(

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What is the answer to y=(2x+5)(x-2) in standard form

docker41 [41]

Answer:

i think it is Rewrite in Standard Form y=2x+5. y=2x+5 y = 2 x + 5.

Step-by-step explanation:

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3 years ago

Celina and Richard spend a certain amount of money from their money box each month to buy plants.

loris [4]

Answer:

100

Step-by-step explanation:

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3 years ago

How do you do this? Yeah

Aliun [14]

Answer:

Step-by-step explanation:

You have to plug -2 into every x in the function, so:

(-2)^2 - 3 (-2) + 7

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3 years ago

Pizza Time has collected data about customer pizza topping preferences. They have calculated that P(pepperoni) = 0.7, P(olives)

inn [45]

We are given with the probabilities P(pepperoni) = 0.7, P(olives) = 0.6, and P(pepperoni or <span>olives) = 0.8. in this case, we are asked to determine P(pepperoni and olives) that is determined from P(pepperoni) + P(olives) - P(pepperoni or olives) equal then to 0.7 + 0.6 - 0.8 equal to 0.5</span>

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3 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

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3 years ago