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Ymorist [56]
3 years ago
6

Molecules of 1-bromopropane and 2-bromopropane differ in

Chemistry
2 answers:
RoseWind [281]3 years ago
8 0
Molecules of 1-bromopropane and 2-bromopropane differ in<span>(1) molecular formula.</span>
zvonat [6]3 years ago
5 0

Answer: (2) structural formula

Explanation:-

The compounds having similar molecular formula but different arrangement of atoms or groups in space are called isomers and the phenomenon is called as isomerism.  

1-bromopropane and 2-bromopropane are position isomers which have same molecular formula but different position of the functional groups attached.

The chemical formula for both the compounds 1-bromopropane and 2-bromopropane is CH_3CH_2CH_2Br. Thus both have same molecular formula , 3 carbon atoms per molecule and 1 bromine atom per molecule.

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7.5 moles of nitrogen gas (N2) is formed in the following reaction. How many grams
AfilCa [17]

Answer:

Mass = 255 g

Explanation:

Given data:

Number of moles of nitrogen = 7.5 mol

Mass of ammonia formed = ?

Solution:

Chemical equation:

3H₂ + N₂      →    2NH₃

Now we will compare the moles of nitrogen and ammonia.

             N₂         :        NH₃

               1          :         2

              7.5       :       2/1×7.5 = 15

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 15 mol × 17 g/mol

Mass = 255 g

6 0
3 years ago
The compound cisplatin, Pt(NH3)2Cl2, has been studied extensively as an antitumor agent.___K2PtCl4 (aq) + ___NH3 (aq)  ___Pt(NH
Lostsunrise [7]

Mass of cisplatin can be made : 144.6 g

<h3>Further explanation</h3>

Given

Reaction(unbalanced)

K2PtCl4 (aq) + ___NH3 (aq)  ___Pt(NH3)2Cl2 (s) + ___KCl (aq)

200 g of K2PtCl4

Required

mass of cisplatin  Pt(NH3)2Cl2

Solution

Balanced equation

K₂PtCl₄ (aq) + 2NH₃ (aq) ⇒Pt(NH₃)₂Cl₂ (s) + 2KCl (aq)

mol of K₂PtCl₄(MW=2.39+195+4.35.5=415 g/mol) :

mol = mass : Mw

mol = 200 : 415

mol = 0.482

From equation, mol ratio K₂PtCl₄ : Pt(NH₃)₂Cl₂ = 1 : 1, so mol Pt(NH₃)₂Cl₂ = 0.482

Mass of cisplatin Pt(NH₃)₂Cl₂(MW=195+2.14+6.1+2.35.5=300 g/mol) :

mass = mol x MW

mass = 0.482 x 300

mass = 144.6 g

8 0
3 years ago
If you want to prepare 2.00 L of a 0.800 M NaNO_3 solution from a NaNO_3 stock solution that is 1.5 M in concentration, how many
Leya [2.2K]

1066.7 ml of the stock solution must start with, preparing 2.00 L of a 0.800 M NaNO3 solution.

<h3>What is volume?</h3>

Volume is the space occupied by a three-dimensional object.

By the formula \rm M_1V_1= M_2V_2

M1 is the initial molarity, 1.5 M

M2 is the final molarity, 0.800 M

V1 is the initial volume

V2 is the final volume, 2.00 L

Putting the values in the equation

\rm 1.5\;M \times V_1= 0.800\;M \times 2.00\;L\\\\V_1 = \dfrac{ 0.800\;M \times 2.00\;L}{1.5\;M} = 1066.7\;ml

Thus, the initial volume is 1066.7 ml

Learn more about volume

brainly.com/question/1578538

#SPJ1

3 0
3 years ago
Draw the product formed when the following diene is treated with one equivalent of HCl. Do not show stereochemistry in your answ
garri49 [273]

Answer:

4-chloro-4-methyl-cyclohexene.

Explanation:

Hello,

On the attached picture you will find the chemical reaction forming the required product, 4-chloro-4-methyl-cyclohexene. In this case, according to the Markovnicov’s rule, it is more likely for the chlorine to be substituted at the carbon containing the methyl radical in addition to the hydrogen to the next carbon to break the double bond and yield the presented product.

Best regards.

6 0
3 years ago
Which of these is an example of food engineering
iogann1982 [59]
I don't know which ones r, could u add options, maybe?
3 0
4 years ago
Read 2 more answers
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