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Ymorist [56]
3 years ago
6

Molecules of 1-bromopropane and 2-bromopropane differ in

Chemistry
2 answers:
RoseWind [281]3 years ago
8 0
Molecules of 1-bromopropane and 2-bromopropane differ in<span>(1) molecular formula.</span>
zvonat [6]3 years ago
5 0

Answer: (2) structural formula

Explanation:-

The compounds having similar molecular formula but different arrangement of atoms or groups in space are called isomers and the phenomenon is called as isomerism.  

1-bromopropane and 2-bromopropane are position isomers which have same molecular formula but different position of the functional groups attached.

The chemical formula for both the compounds 1-bromopropane and 2-bromopropane is CH_3CH_2CH_2Br. Thus both have same molecular formula , 3 carbon atoms per molecule and 1 bromine atom per molecule.

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What are the functions of ammonia in the solvay process​
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Which of the following is a true
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a fixed amount of gas at 25.0 degrees Celsius occupies a volume of 10.0 L when the pressure is 629 torr. Use Charles law to calc
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A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re
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Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2  = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = \frac{Presssure due to CO_2}{Total pressure}

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= 0.735

Also; for Kr ; we have

Kr = \frac{0.193}{0.729}

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Mass of Kr = 0.265 *  83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is  as follows:

% CO2 = \frac{32.34}{54.54}* 100 %

= 0.5930

= 59.30%  

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr =\frac{22.20}{ 54.54} * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0
3 years ago
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