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BaLLatris [955]
3 years ago
5

Acetic acid (CH3COOH) reacts with water to form the acetate ion and the hydronium ion:

Chemistry
2 answers:
weeeeeb [17]3 years ago
5 0

Answer:A

Explanation:

WITCHER [35]3 years ago
4 0

Answer:

A

Explanation:

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Answer pls pls plss this is my mock
Serggg [28]

Answer:

if this is a mock then just guess

Explanation:

4 0
3 years ago
The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 H
neonofarm [45]

Answer:

25 coolers are need to be produce and sell in order to minimize the cost.

Explanation:

C = 0.005x^2-0.25x+12 ..[1]

Differentiating the given expression with respect to dx.

\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}

\frac{dC}{dx}=0.01x-0.25+0

Putting ,\frac{dC}{dx}=0

0=0.01x-0.25+0

0.01x=0.25

x = 25

Taking second derivative of expression [1]

\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01

\frac{d^2C}{dx^2}>0 (minima)

25 coolers are need to be produce and sell in order to minimize the cost.

3 0
3 years ago
When an acidic molecule is added to water it will ____________ the pH of the solution because it increases the number of free __
Dahasolnce [82]
Lower the pH because increased number of free hydrogen ions
5 0
3 years ago
3. What was the temperature in
Alexeev081 [22]
Q = mcΔT

m = 75 g
c = 4.25 J/gram°C
q = 2450 J

q/mc = ΔT

2450/(75 • 4.25) = 7.7°C

The temperature increased by 7.7°C.
6 0
2 years ago
A quantity of 7.480 g of an organic compound is dissolved in water to make 300.0 mL of solution. The solution has an osmotic pre
Serga [27]

Answer:

C5H6N2O3

Explanation:

First the empirical formulas

C= 41.8÷12= 2.48

H= 4.7÷1= 4.7

O= 37.3÷ 16= 2.33

N= 16.3÷14 = 1.16

Divide by the smallest

C= 3.48/1.16=3

H= 4.7/1.16=4.1

O= 2.33/1.16=2

N= 1.16/1.16=1

Therefore empirical formula = C3H4NO2

To calculate molecular formula for osmotic pressure,

π= cRT

Or

π=cgRT/M where cg is in g/liter & T is temperature in Kelvin. Thus

π= (7.480*0.0821*300)/ M

M= 184.23/1.43

M= 128.83

To find molecular Formula

Molecular Mass= (empirical mass)n

128.83= (C3H4NO2)n

128.83= 86n

n= 1.5

Therefore the molecular formula

(C3H4NO2)1.5

= C4.5H6N1.5O3

Approximately

C5H6N2O3

7 0
3 years ago
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