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kirill [66]
3 years ago
5

Write a hypothesis about the pH level of common household solutions based on what you know about their physical and chemical pro

perties. Use the format of "if . . . then . . . because . . .” and be sure to answer the lesson question "How is pH used to determine if a solution is acidic or basic?”
Chemistry
2 answers:
ddd [48]3 years ago
7 0

Sample Response: If a solution is an acid, then it will have a pH below 7, and if the solution is a base, it will have a pH above 7 since the pH value is determined by the concentration of H+ and OH– ions.

docker41 [41]3 years ago
5 0

If pH is less than seven (pH<7), solution is acidic.

If pH is equal seven (pH = 7), solution is neutral.  

If pH is greater than seven (pH > 7), solution is basic.  

Some examples:

1) Acidic - gastric juices pH 1, lemon juice pH 2.2, tomato juice pH 4.

2) Neutral - salt solution pH 7.

3) Alkaline - baking soda pH 9, bleach pH 13.

pH is a numeric scale used to specify the acidity or basicity of an aqueous solution.



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A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom
Taya2010 [7]

Answer:

28/95 = 29.,5 % of Arsine decomposed

Explanation:A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which tem- perature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?

Answer in units of %.

initial pressure 332 Torr initial volume 0.46 L initial temperature 223K

final pressure 488 Torr final volume 0.46 L final 273 K

Torr is 1/760 atm 332 torr = 0.437 atm 488 Torr =0.642 atm

PV = nRT so n=RT/PV

INITIAL n= 0.082 X 223/(0.437)(0.46) = 91 moles

final n= 0.082 X 273 / (.437)(488) = 105 moles

2AsH3----------> 2As + 3H2

x moles of Arsine decomposed to make 1.5 moles of H2

the final number of moles was

(91 -X)+ 1.5 X = 105 moles

91 + 0.5 X = 105

0.5 X = 14

X =28

CHECK

if 28 moles of Arsine , then the container would have

91 --28 + 1.5(28) = 91 +14 =105 check

so 28/95 = 29.,5 % of Arsine decomposed

Your answer

(quit)

polyalchemVirtuoso

Answer:

Explanation:

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