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Novay_Z [31]
3 years ago
5

Using this figure A’ is the______Of A.

Mathematics
1 answer:
givi [52]3 years ago
8 0

Answer:

Reflection

Step-by-step explanation:

Figure A' is the reflection of A as it is reflected from A'

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3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h
lys-0071 [83]

Answer:

See below.

Step-by-step explanation:

The rocket's  flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where  u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t  - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards  with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis  gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

6 0
3 years ago
Read 2 more answers
Which expression is equivalent to 0.25(2d + 1) ? please help meh
wolverine [178]

Answer:

I think it is 0.50d + 0.25

PLZ CORRECT ME IF I AM WRONG PLEASE AND THANK YOU

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
3 years ago
three tanks are capable of holding 108 litres, 168 litres and 180 litres of milk. determine the capacity of the greatest vessel
SpyIntel [72]

A vessel of 7,560 liters

Step-by-step explanation:

This means finding the Least Common Multiple for;

108 168 180

We begin by finding the multiples of each number;

Multiples of 108:

108, 216, 324, 432, 540, 648, 756, 864, 972, 1080, 1188, 1296, 1404, 1512, 1620, 1728, 1836, 1944, 2052, 2160, 2268, 2376, 2484, 2592, 2700, 2808, 2916, 3024, 3132, 3240, 3348, 3456, 3564, 3672, 3780, 3888, 3996, 4104, 4212, 4320, 4428, 4536, 4644, 4752, 4860, 4968, 5076, 5184, 5292, 5400, 5508, 5616, 5724, 5832, 5940, 6048, 6156, 6264, 6372, 6480, 6588, 6696, 6804, 6912, 7020, 7128, 7236, 7344, 7452, <u>7560</u>, 7668, 7776

Multiples of 168:

168, 336, 504, 672, 840, 1008, 1176, 1344, 1512, 1680, 1848, 2016, 2184, 2352, 2520, 2688, 2856, 3024, 3192, 3360, 3528, 3696, 3864, 4032, 4200, 4368, 4536, 4704, 4872, 5040, 5208, 5376, 5544, 5712, 5880, 6048, 6216, 6384, 6552, 6720, 6888, 7056, 7224, 7392, <u>7560</u>, 7728, 7896

Multiples of 180:

180, 360, 540, 720, 900, 1080, 1260, 1440, 1620, 1800, 1980, 2160, 2340, 2520, 2700, 2880, 3060, 3240, 3420, 3600, 3780, 3960, 4140, 4320, 4500, 4680, 4860, 5040, 5220, 5400, 5580, 5760, 5940, 6120, 6300, 6480, 6660, 6840, 7020, 7200, 7380, <u>7560</u>, 7740, 7920

The Least Common Multiple for the 3 number is;

= 7560

Therefore a vessel of 7,560 liters fills each one of them an exact number of times with no remainder.

Learn More:

For more on Least Common Multiple check out;

brainly.com/question/11978021

#LearnWithBrainly

5 0
3 years ago
Help i dont know what to do i give brainlist
Y_Kistochka [10]

Answer:

473 yd^3

Step-by-step explanation:

The surface area of the square base is (11 yd)^2, or 121 yd^2.

The surface area of one of the slanting sides of the pyramid is

A = (1/2)(b)(h), which comes to A = (1/2)(11 yd)(16 yd) = 88 yd^2.

Thus, four such sides have a combined surface area of 352 yd^2.

Combining the surface areas of the slanting sides with the base area yields 473 yd^3

4 0
3 years ago
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