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3 years ago

Write an expression for twelve divided by a number

Mathematics

1 answer:

Rom4ik [11]3 years ago

8 0

12 ÷ 3= 4. Hope this helps. ;)

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6 multiplication problems that ar involved in the solving of 325×89

gogolik [260]

325*89.1

Let's decompose this into:

325 = 300 + 25

89.1 = 80 + 9 + 0.1

Then we have the multiplication:

(300 + 25)*(80 + 9 + 0.1)

Let's distribute the multiplication:

300*80 + 300*9 + 300*0.1 + 25*80 + 25*9 + 25*0.1

So now we have 6 multiplications that are a lot easier to solve than the initial one that we had.

Then the list of six multiplications involved in solving this problem are:

300*80 = 24,400

300*9 = 2,700

300*0.1 = 30

25*80 = 2,000

25*9 = 225

25*0.1 = 2.5

Now we add all of those and get:

325*89.1 = 24,400 + 2,700 + 30 + 2,000 + 225 + 2.5 = 28,957.5

4 0

3 years ago

Lol i need help again plzz

Len [333]

X would equal 81 because the square root of 81 is 9.

9 x 9 = 81

7 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided.

rodikova [14]

Answer:

$\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}$

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³ - 7x + 4

(b) Create a subtraction problem using the two functions

ƒ(x) = 9x³ + 2x² - 5x + 4

-g(x) = <u>-(5x³ - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

ƒ(x) = 9x³ + 2x² - 5x + 4

-g(x) = <u>-(5x³ - 7x + 4) </u>

ƒ(x) -g(x) = 4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

$\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}$

5 0

3 years ago

Mathematics

Vladimir [108]

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

4 0

1 year ago

How do you subtract 1 integer by another

nikdorinn [45]

Use absolute value. If both signs are negative you will get a negative number. if both are positive you get positive. if the signs are different, subtract the smaller absolute value from the larger absolute value.

8 0

3 years ago

Read 2 more answers