Answer:
x = -17/4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
3x + 5(2 + x) = 4x - 7
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute 5: 3x + 10 + 5x = 4x - 7
- [Addition] Combine like terms: 8x + 10 = 4x - 7
- [Subtraction Property of Equality] Subtract 4x on both sides: 4x + 10 = -7
- [Subtraction Property of Equality] Subtract 10 on both sides: 4x = -17
- [Division Property of Equality] Divide 4 on both sides: x = -17/4
V=π * r^2 * h/3 = π * 2^2 * 8/3 ≈ 33.51032 or about 34 units^2
Answer:
(a) ΔARS ≅ ΔAQT
Step-by-step explanation:
The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.
In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.
The desired congruence statement in Step 3 is ...
ΔARS ≅ ΔAQT
Answer:
C. 8x - 3y = 5
Step-by-step explanation:
7 - 3(x - y) = 5x + 2
Standard form: Ax + By = C
7 -3x + 3y = 5x + 2
7 -8x + 3y = 2
-8x + 3y = -5
Divide by -1 to each number
8x - 3y = 5
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
