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Vikki [24]
3 years ago
11

What is the length of AC pleasee help

Mathematics
1 answer:
fgiga [73]3 years ago
3 0
Do the Pythagorean theorem... a2+b2=c2. C will always be the opposite of the right triangle. First find the length of AE, which is 18. You plug everything into the formula and you end up with 135.94 round it up and it’s 136. The answer is B=136
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Write an equation of the line that passes through point (2,-4) and has the slope m= 1/2 <br> y =
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Answer:

tHe can discuss intelligently the current political affairs. Television is a machine that ought to be used intelligently. It is necessary to think intelligently before performing any action.

Step-by-step explanation:

5 0
2 years ago
Lisa wants to buy material for her dress. If she buys 7metres, she is 1 dollar short. If she buys 5metres, 5 dollars is left ove
Ede4ka [16]

Answer:

She has 15 dollar.

Explanation

If every meter costs 2 dollars, then 5 meter would cost 10 dollars and 7 meter would cost 14 dollar. Now we take a number when subtracted from 10, we get 5 dollar and when the same number subtracted from 14 we get 1 dollar left. Now if we take 15 dollar, you'll see that when you subtract 10 from it you get 5 dollar and when you subtract 14 from it you get 1 dollar. Therefore 15 satisfies the given condition in the question.

$15 - $10 = $5

$15 - $14 = $1

4 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
What is the difference between a linear pair and angles on a straight line ​
expeople1 [14]

Answer:

Linear pair is two adjacent angles whose non-common side from opposite rays. the line through points A., B and C is straight line. if two angles from a linear pair the angle are supplementary.

7 0
3 years ago
I need help please I’m confused
Ahat [919]

Answer:

The answer is 50 degrees

Step-by-step explanation:

The small box at the corner of the triangle indicates that the triangle is exactly 90 degrees, or a right angle. In order to solve the expression, you would need to do 40 + x = 90, which would be x = 50

8 0
3 years ago
Read 2 more answers
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