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7nadin3 [17]
2 years ago
7

An airplane takes off 200 yards in front of a 60 foot building. At what angle of elevation must the plane

Mathematics
1 answer:
fenix001 [56]2 years ago
4 0

Answer:

16.69°

Step-by-step explanation:

Given that,

Height of the building, h = 60 foot

Distance from the base of the building, b = 60 foot

We need to find the angle of elevation must the plane takes off in order to avoid crashing into the building. So,

\tan\theta=\dfrac{60}{200}\\\\\theta=\tan^{-1}\dfrac{60}{200}\\\\=16.69^{\circ}

So, the required angle is 16.69°.

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<h3>Answer:  Approximately 56 inches</h3>

===========================================================

Explanation:

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