Question

An airplane takes off 200 yards in front of a 60 foot building. At what angle of elevation must the plane

Answer 1

Answer:

16.69°

Step-by-step explanation:

Given that,

Height of the building, h = 60 foot

Distance from the base of the building, b = 60 foot

We need to find the angle of elevation must the plane takes off in order to avoid crashing into the building. So,

$\tan\theta=\dfrac{60}{200}\\\\\theta=\tan^{-1}\dfrac{60}{200}\\\\=16.69^{\circ}$

So, the required angle is 16.69°.