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lianna [129]
2 years ago
10

Number 14? Please :)

Chemistry
1 answer:
ASHA 777 [7]2 years ago
4 0
Evaporated is the answer
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In your OWN WORDS, describe what the “Law of Conservation of Energy” is.
agasfer [191]
Energy cannot be destroyed or created, but energy could be transformed or transferred. For example a skiier skiing from the mouth can have potential energy transferred into kinetic energy.
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2 years ago
For an experiment, you place 15 g of ice with a temperature of -10 C into a cup and label
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The correct answer is c. Temperature is the average kinetic energy of a sample so if two samples have the same temperature they will also have the same average kinetic energy. I hope this helps. Let me know if anything is unclear.
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What is the total mass of D-glucose dissolved in a 2-μL aliquot of the solution used for this experiment?
RideAnS [48]

Answer:

The total mass of D-Glucose dissolved in a 2μL aliquot is 1 E-4 g

Explanation:

providing a solution to 5% weight-volume as found in commerce:

⇒ % 5 = (5g d-glucose/ 100 mL sln)×100

⇒ 0.05 =  g C6H12O6/mL sln

⇒ g C6H12O6 = (2 μL sln)×(0.001 mL/μL)×(0.05 g C6H12O6/mL sln)

⇒ g C6H12O6 = 1 E-4 g C6H12O6

5 0
3 years ago
Calculate the mass in grams for 2.28 moles of N2.
borishaifa [10]

Answer: 63.9

Explanation:

7 0
2 years ago
A self-contained underwater breathing apparatus (SCUBA) uses canisters containing potassium superoxide. The superoxide consumes
emmainna [20.7K]

Answer:

52.0004 grams of mass of potassium superoxide  is required

Explanation:

Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.

Pressure of the gas,P = 767 mm Hg = 0.9971 atm

Temperature of the gas,T = 22.0 °C = 295.15 K

Using an ideal gas equation to calculate the number of moles.

PV=nRT

n=\frac{0.9971 atm\times 8.90 L}{0.0821 atm L/mol K\times 295.15 K}

n = 0.3662 mol

4KO_2(s)+2CO_2(g)\rightarrow 2K_2CO_3(s)+3O_2(g)

According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.

Then 0.3662 mol of  of carbon-dioxide will react with:

\frac{4}{2}\times 0.3662 mol=0.7324 mol of potassium superoxide.

Mass of 0.7324 mol potassium superoxide:

0.7324 mol × 71 g/mol = 52.0004 g

52.0004 grams of mass of potassium superoxide is required.

8 0
3 years ago
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