Answer:
3Mg(OH)2 + 2H3PO4 = Mg3(PO4)2 + 2H3O
Explanation:
Answer:
V₂ = 448.44 L
Explanation:
Given data:
Initial volume = 5.00 L
Initial temperature = 24°C
Final volume = ?
Final temperature = -27000°C
Solution:
Final temperature = -27000 + 273 = 26727 K
Initial temperature = 24 +273 = 297 K
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 5.00 L × 26727 K / 297 k
V₂ = 133635 L.K / 298 K
V₂ = 448.44 L
Answer:
hope this will help you......
Answer:
2H2S + 3O2 → 2SO2 + 2H2O
Explanation:
Step 1: Data given
Hydrogen sulfide = H2S
Oxygen = O2
sulfur dioxide = SO2
water = H2O
Step 2: The unbalanced equation
H2S + O2 → SO2 + H2O
Step 3: Balancing the equation
H2S + O2 → SO2 + H2O
On the left side we have 2x O (in O2) and on the right side we have 3x O (2x in SO2 and 1x in H2O). To balance the amount of O, we have to multiply O2 (on the left side) by 3 and SO2 and H2O on the right side by 3.
H2S + 3O2 → 2SO2 + 2H2O
On the right side we have 4x H and on the left side we have 2x H. To balance the amount of H, we have to multiply H2S by 2.
Now the equation is balanced.
2H2S + 3O2 → 2SO2 + 2H2O
The compound of the chemical is altered
