Answer:
Molarity= 0.071M
Explanation:
Molar mass of NaNO3= 23+14+(16*3)=85
n= m/M = 30/85= 0.353mol
V= 5L
Applying
n= CV
0.353= C×5
Simplify
C= 0.071M
One kg of oxygen is 0.3977 liters so:
Answer:
369.4 g.
Explanation:
- The chemical reaction of reacting hydrogen with oxygen to produce water is:
<em>H₂ + 1/2 O₂ → H₂O.</em>
- From the law of conservation of mass states that <em>the mass does not destroyed or created from nothing but it can converted from from to another one.</em>
- The mass of the reactants = the mass of the products
∴<em> The mass of hydrogen + the mass of oxygen = the mass of water.</em>
∴ The mass of oxygen = the mass of water - the mass of hydrogen = (416.0 g) - (46.6 g) = 369.4 g.
<u>Answer:</u> The volume of stock solution of ammonia that is needed is 48.67 mL
<u>Explanation:</u>
To calculate the volume of stock solution, we use the equation:
where,
are the molarity and volume of the stock ammonia solution
are the molarity and volume of diluted ammonia solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution of ammonia that is needed is 48.67 mL
