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Lubov Fominskaja [6]
4 years ago
10

Missing length?? 3 cm 8 cm i need big help

Mathematics
1 answer:
nadezda [96]4 years ago
8 0

Answer: 8.5 (rounded)

Step-by-step explanation:

a squared + b squared = c squared

3 squared= 9

8 squared= 64

64+9=73

the square root of 73 is 8.5 (rounded)

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Determine if the sequence is arithmetic. If it is, find the common difference. Is the sequence a function ?
BaLLatris [955]
6)\\r=a_{n+1}-a_n\to r=a_2-a_1=a_3-a_2=a_4-a_3=...\\\\a_1=-7;\ a_2=-10;\ a_3=-11;\ a_4=-13\\\\a_2-a_1=-10-(-7)=-10+7=-3\\a_3-a_2=-11-(-10)=-11+10=-1\\\\a_3-a_2\neq a_2-a_1\\\\\text{It's not an arithmetic sequence}


\r=\dfrac{a_{n+1}}{a_n}\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...\\\\8.)\\a_1=4;\ a_2=20;\ a_3=100;\ a_4=500\\\\r=\dfrac{20}{4}=\dfrac{100}{20}=\dfrac{500}{100}=5\\\\10.)\\a_1-30;\ a_2=-45;\ a_3=-50;\ a_4=-65\\\\\dfrac{a_2}{a_1}=\dfrac{-45}{-30}=\dfrac{3}{2}\\\\\dfrac{a_3}{a_2}=\dfrac{-50}{-45}=\dfrac{10}{9}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}
12.)\\a_1=-7;\ a_2=-14;\ a_3=-21;\ a_4=-28\\\\\dfrac{a_2}{a_1}=\dfrac{-14}{-7}=2\\\\\dfrac{a_3}{a_2}=\dfrac{-21}{-14}=\dfrac{3}{2}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}\\\\\text{It's a function}


8 0
3 years ago
Simplify square root of 1008 ( V` Represents the square root sign.)
Alexus [3.1K]
So first factor it
1008=2*2*2*2*3*3*7
group them in similar pairs
1008=(2*2)(2*2)(3*3)*7
now remember we can do
\sqrt{xy}= \sqrt{x} \sqrt{y} so
\sqrt{1008}= (\sqrt{2*2}) (\sqrt{2*2}) (\sqrt{3*3}) (\sqrt{7})=
2*2*3*\sqrt{7}=
12√7

the answer is B

5 0
3 years ago
One zero of x^3 - 4x = 0 is 0 what are the other zeros of the function
myrzilka [38]
So you have x^3 - 4x = 0. What you can do is pull out an x from both x^3 and - 4x so it looks like this:

x( {x}^{2} - 4) = 0

Then you can find a number that makes the part inside the parentheses turn into zero. For beginners, it may be easier to write it out seperately and solve for x.

{x}^{2} - 4 = 0

We need to solve for x, so the first step is to add 4 to both sides, so we get something like this:

{x}^{2} = 4

Then, we can square root both sides to get rid of the power on the x, so it looks like this:

x = \sqrt{4}

Now, every square root has two answers, a positive and a negative. If we look at the bottom example:

{2}^{2} = 4

{( - 2)}^{2} = 4

We can see that both -2 and 2 to the power of two will equal to 4.

So finally, we get:

x = - 2 \: and \: 2

These are the other 'Zero's for the original function. If you are not sure of what a 'Zero' is, it is where the function crosses over the x-axis on a graph.
5 0
3 years ago
How do you put f(8)=-1,f(6)=0 into point slop form?​
Mademuasel [1]

Answer:

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute [SF]:                    m=\frac{0+1}{6-8}
  2. Add/Subtract:                      m=\frac{1}{-2}
  3. Simplify:                               m=\frac{-1}{2}

<u>Step 3: Write Function</u>

<em>Substitute into general form.</em>

  • Point 1: y + 1 = -1/2(x - 8)
  • Point 2: y = -1/2(x - 6)
4 0
3 years ago
15, 16, 20, and 22! PLEASE HELP
Vikentia [17]
The answer for number 16 is 20
7 0
3 years ago
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