Answer:
35
Step-by-step explanation:
Step 1:
JL + KL = JK Equation
Step 2:
22 + 13 = JK Substitution
Answer:
JK = 35 Add
Hope This Helps :)
Answer:
x= 128*
Step-by-step explanation:
180*-52*=128*
Answer:
27% and 37%
Step-by-step explanation:
Percentage of students who oppose the year-round school = 68%
Percentage of students who support the year-round school = 32%
Margin of error = ± 5%
We have to set up the absolute valued equation to find the range(least and greatest) percentages of students who could be in favor of year-round school.
Since, the percentage of students who support the year-round school is 32% and the margin of error is 5%, this means, the difference between 32% and the least and greatest possible percentages is 5%. It can be either +5% or -5%
This thing can be expressed as absolute valued equation as:
| x - 32 | = 5
Here x represents the least and greatest percentages.
Expanding the equation, we can write:
x - 32 = -5 or x - 32 = 5
x = -5 + 32 or x = 5 + 32
x = 27% x= 37%
This means the least percentage of students who be in favor is 27% and the greatest percentage of students is 37%.
Answer:
In step 3
4m = 4 + 4n
-4m = -32 -8n. (step 2)
If you add -4m, 4m you end up with
-4m+4m=-32 -8n + 4n +4
In step 3. the 4 was not added
continuing to solve 4n=-28, n=-7
Answer:
<em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>1</em><em>2</em><em>1</em><em> </em><em>square</em><em> </em><em>meter</em>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>4</em><em>4</em><em> </em><em>meter</em>
Step-by-step explanation:
Area of a square=side*side
=11*11
=<u>1</u><u>2</u><u>1</u><em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>meter</u></em>
Perimeter of a square garden=side*4
=11*4
=44 m
