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irakobra [83]
2 years ago
10

Solve for x. Look at the image attached thanks.

Mathematics
1 answer:
Elina [12.6K]2 years ago
6 0

Answer:

x=2.2

Step-by-step explanation:

You know that for triangle ABC, side AB=10, CB=2 and AD=AB+BD=10+1=11. Given that triangles ABC and AED have the same angles, they are similar triangles.

So we can use the following ratios to solve for ED=x:

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jolli1 [7]

Try it with some random number, like a=3.

       Is "3+0 = 0+3 = 0" true?    No.

If you were doing multiplication, then it would be true, but not with addition.

6 0
3 years ago
PLSSS HELP GIVING 5 POINTS PLUS BRAINLIEST
Serjik [45]
Add all then divided okay hope that helps 5
4 0
3 years ago
Factorise completely 12 x³y - 18 xy²​
jarptica [38.1K]

Answer:

6xy(2x²-3y)

Step-by-step explanation:

factorized completely

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2 years ago
an electronic store has television sets marked doen 30%.What is the total sale price of five television sets that regularly sell
pashok25 [27]

Answer:

$192731932

Step-by-step explanation:

3 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
2 years ago
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