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viva [34]
3 years ago
8

How to you solve. 4+36÷(10-8)^2•3+7

Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0

\bf 4+36\div (10-8)^2\cdot 3+7\implies \stackrel{\mathbb{PEMDAS}}{4+36\div (\stackrel{\downarrow }{2})^2\cdot 3+7}
\\\\\\
4+36\div \stackrel{\downarrow }{4}\cdot 3+7\implies 4+\stackrel{\downarrow }{9}\cdot 3+7\implies 4+\stackrel{\downarrow }{27}+7
\\\\\\
\stackrel{\downarrow }{31}+7\implies 38

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56 in²
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The area of the remaining board is [(L × B) - (l × b)].

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So, For this purpose, we know that the

Area of rectangle is the region occupied by a rectangle within its four sides or boundaries. The area of a rectangle depends on its sides.

From the given information:

Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.

And

Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.

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The area of the bigger rectangle is:

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Then the area of the remaining board will be:

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Area of remaining board= (L × B) - (l × b)

Thus, The area of the remaining board is [(L × B) - (l × b)].

Learn more about Area here

brainly.com/question/8409681

Disclaimer: This question was incomplete. Please find the full content below.

Question:

A rectangle is removed from the middle of a larger rectangular shaped board. What is the area of the remaining board?

#SPJ9

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