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3 years ago

How to you solve. 4+36÷(10-8)^2•3+7

1 answer:

Nookie1986 [14]3 years ago

5 0

$\bf 4+36\div (10-8)^2\cdot 3+7\implies \stackrel{\mathbb{PEMDAS}}{4+36\div (\stackrel{\downarrow }{2})^2\cdot 3+7}
\\\\\\
4+36\div \stackrel{\downarrow }{4}\cdot 3+7\implies 4+\stackrel{\downarrow }{9}\cdot 3+7\implies 4+\stackrel{\downarrow }{27}+7
\\\\\\
\stackrel{\downarrow }{31}+7\implies 38$

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The coordinates of verticales diagonal SU are S(4,1), and U(-2,-1),

By applying distance formula:

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

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