Question

How to you solve. 4+36÷(10-8)^2•3+7

Answer 1

$\bf 4+36\div (10-8)^2\cdot 3+7\implies \stackrel{\mathbb{PEMDAS}}{4+36\div (\stackrel{\downarrow }{2})^2\cdot 3+7} \\\\\\ 4+36\div \stackrel{\downarrow }{4}\cdot 3+7\implies 4+\stackrel{\downarrow }{9}\cdot 3+7\implies 4+\stackrel{\downarrow }{27}+7 \\\\\\ \stackrel{\downarrow }{31}+7\implies 38$