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evablogger [386]

2 years ago

5

Find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length.

1 answer:

Degger [83]2 years ago

3 0

find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length

To find the perimeter of a triangle we add all the sides of the triangle

The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches

Perimeter of a triangle =

15 inches + 15 inches + 21 inches = 51 inches

So 51 inches is the perimeter

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Please explain this to me UwU

ki77a [65]

Each answer possibility is a coordinate and represents a variety of an (x,y) point. The equation states that y = 32x + 27, so to find the correct answer, u must find the (x,y) coordinate that makes each side equal to the other. Plug in each number accordingly...

(y) = 32(x) + 27

a. (248) = 32(8) + 27

b. (379) = 32(11) + 27

c. (354) = 32(6) + 27

d. (288) = 32(9) + 27

now it’s just a matter of simplifying to see which equation is true.

a. 248 =/ 283

b. 379 = 379

c. 354 =/ 219

d. 288 =/ 315

The only equation that is true is B.

7 0

3 years ago

Read 2 more answers

Can someone please help me?

Alisiya [41]

Answer:

Step-by-step explanation:

That'd be the Substitution Property. Substitute -2 for x in x + 8 = 6 and arrive at the true statement 6 = 6.

4 0

2 years ago

1. A pond has 85 frogs, 20% of the frogs are green the rest are orange, brown, and yellow. How many frogs are green?

alexandr402 [8]

Answer:

17 green frogs

Step-by-step explanation:

You need to multiply the decimal form of 20% by 85.

To find the decimal form of a percent you take the decimal (20.00) and move it twice to the left (20.00 ---> .2000)

Now, multiply by .2 by 85

(.2)(85) = 17

Therefore, 17 frogs in the pond of 85 frogs are green

<em>Hope this helps!!</em>

<em>- Kay :)</em>

4 0

2 years ago

Let f(x) =7x-13. Find f -1(x)

muminat

If you’re trying to find f(-1) it would be -20

5 0

2 years ago

Read 2 more answers

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

3 years ago